이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef pair<ll,ll> p;
typedef pair<ll, p> tri;
typedef vector<ll> v;
typedef vector<v> vv;
typedef vector<p> vp;
typedef vector<tri> vtri;
typedef vector<vtri> vvtri;
typedef vector<vvtri> vvvtri;
typedef vector<vv> vvv;
typedef vector<bool> vb;
typedef vector<vb> vvb;
typedef vector<vvb> vvvb;
typedef vector<p> vp;
typedef vector<vp> vvp;
typedef vector<vvp> vvvp;
typedef vector<vvvp> vvvvp;
#define double long double
typedef vector<double> vd;
typedef vector<vd> vvd;
typedef vector<vvd> vvvd;
const ll mod = 1e9 + 7;
const ll INF = 1e18;
#define f first
#define s second
#define pb push_back
#define eb emplace_back
#define loop(a) for (ll i = 0; i < a; i++)
#define setmin(a, b) a = min(a, b)
#define setmax(a, b) a = max(a, b)
#define all(v) v.begin(), v.end()
void update(v &st, ll i, ll val)
{
ll n = st.size() / 2;
i += n;
st[i] = val;
i /= 2;
while (i > 0)
{
st[i] = min(st[2 * i], st[2 * i + 1]);
i /= 2;
}
}
ll query(v &st, ll l, ll r)
{
ll n= st.size() / 2;
l += n; r += n;
ll res = INF;
while (l <= r)
{
if (l % 2 == 1)
{
res = min(res, st[l]);
l++;
}
if (r % 2 == 0)
{
res = min(res, st[r]);
r--;
}
l /= 2; r /= 2;
}
return res;
}
ll lastSmaller(v &st, ll x)
{
ll i = 1;
ll n = st.size() / 2;
if (st[1] >= x) return -1;
while (i < n)
{
if (st[2 * i + 1] < x) i = 2 * i + 1;
else i *= 2;
}
return i - n;
}
int main()
{
ios_base::sync_with_stdio(false);cin.tie(NULL);cout.tie(NULL);
ll N, D;
cin >> N >> D;
v A(N);
for (ll i =0; i < N; i++) cin >> A[i];
ll n = pow(2, ceil(log2(N + 1)));
v st(2 * n, INF);
update(st, 0, -INF);
vector<multiset<ll>> endings(N + 1);
endings[0].insert(-INF);
for (ll i = 1; i <= N; i++) endings[i].insert(INF);
v res(N, -1);
ll best = 0;
for (ll i = 0; i < N; i++)
{
ll add = lastSmaller(st, A[i]);
if (add != -1)
{
endings[add + 1].insert(A[i]);
best = max(best, add + 1);
update(st, add + 1, *endings[add + 1].begin());
res[i] = add + 1;
}
if (i >= D && res[i - D] != -1)
{
endings[res[i - D]].erase(endings[res[i - D]].find(A[i - D]));
update(st, res[i - D], *endings[res[i - D]].begin());
}
}
cout << best << "\n";
return 0;
}
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