Submission #1083757

#TimeUsernameProblemLanguageResultExecution timeMemory
10837578pete8Raspad (COI17_raspad)C++17
100 / 100
421 ms121168 KiB
#include<iostream> #include<stack> #include<map> #include<vector> #include<string> #include<cassert> #include<unordered_map> #include <queue> #include <cstdint> #include<cstring> #include<limits.h> #include<cmath> #include<set> #include<algorithm> #include <iomanip> #include<numeric> #include<bitset> using namespace std; #define ll long long #define f first #define s second #define pii pair<int,int> #define ppii pair<int,pii> #define vi vector<int> #define pb push_back #define all(x) x.begin(),x.end() #define rall(x) x.rbegin(),x.rend() #define F(n) for(int i=0;i<n;i++) #define lb lower_bound #define ub upper_bound #define fastio ios::sync_with_stdio(false);cin.tie(NULL); #pragma GCC optimize ("03,unroll-lopps") #define int long long using namespace std; const int mod=1e9+7,mxn=1e5+5,inf=1e18,minf=-1e18,lg=30,valbound=1e9; //#undef int int k,m,q,p,h,w,n; void setIO(string name){ ios_base::sync_with_stdio(0); cin.tie(0); freopen((name+".in").c_str(),"r",stdin); freopen((name+".out").c_str(),"w",stdout); } int grid[mxn+10][55],vis[mxn+10][55]; int ans=0,x=inf,y=minf; int u[8]={1,-1,0,0,1,1,-1,-1},r[8]={0,0,1,-1,1,-1,1,-1}; void get(int cx,int cy){ x=min(x,cx); y=max(y,cx); vis[cx][cy]=1; for(int i=0;i<8;i++){ int nx=cx+u[i],ny=cy+r[i]; if(nx<=0||nx>n||ny<=0||ny>m){ x=1,y=n;//border case ->dont count continue; } if(vis[nx][ny])continue; if(grid[nx][ny])continue; get(nx,ny); } } int32_t main(){ cin>>n>>m; for(int i=1;i<=n;i++){ string a;cin>>a; for(int j=0;j<m;j++)grid[i][j+1]=a[j]-'0'; } for(int i=1;i<=n;i++)for(int j=1;j<=m;j++)if(grid[i][j])ans+=(i*(n-i+1)); for(int i=2;i<=n;i++)for(int j=1;j<=m;j++)if(grid[i][j]&&grid[i-1][j])ans-=((i-1)*(n-i+1)); for(int i=1;i<=n;i++)for(int j=2;j<=m;j++)if(grid[i][j]&&grid[i][j-1])ans-=(i*(n-i+1)); for(int i=2;i<=n;i++)for(int j=2;j<=m;j++)if(grid[i][j]&&grid[i][j-1]&&grid[i-1][j]&&grid[i-1][j-1])ans+=((i-1)*(n-i+1)); //case 4 for(int i=1;i<=n;i++)for(int j=1;j<=m;j++)if(!vis[i][j]&&grid[i][j]==0){ x=n,y=1; get(i,j); ans+=((x-1)*(n-y)); } cout<<ans; } /* what if we look at each cell as a seperated node then we can see that the vertical edges connect 2 node together so we will know that l,r that cover i will have comp -=1 how about the horizontal edges? we can make all the node that shared vertical edge into one comp we can make a graph with only horizontal edges we can see that for a cycle let x,y = min and max row in the cycle we can see that one of the edge is useless as it connect 2 of the same comp when there are multiple cycle in a cycle we will take min,max from the small cycle each cycle will make a hole? except for the size 4 we can oversubtract then add back by counting holes? 4 4 1101 1111 1010 1011 5 7 0100010 0111110 0101001 1111011 0100100 4 12 011111010111 110000101001 110111101111 111101111111 */

Compilation message (stderr)

raspad.cpp:32:40: warning: bad option '-funroll-lopps' to pragma 'optimize' [-Wpragmas]
   32 | #pragma GCC optimize ("03,unroll-lopps")
      |                                        ^
raspad.cpp:38:23: warning: bad option '-funroll-lopps' to attribute 'optimize' [-Wattributes]
   38 | void setIO(string name){
      |                       ^
raspad.cpp:46:23: warning: bad option '-funroll-lopps' to attribute 'optimize' [-Wattributes]
   46 | void get(int cx,int cy){
      |                       ^
raspad.cpp:61:14: warning: bad option '-funroll-lopps' to attribute 'optimize' [-Wattributes]
   61 | int32_t main(){
      |              ^
raspad.cpp: In function 'void setIO(std::string)':
raspad.cpp:40:9: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
   40 |  freopen((name+".in").c_str(),"r",stdin);
      |  ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
raspad.cpp:41:9: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
   41 |  freopen((name+".out").c_str(),"w",stdout);
      |  ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
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