이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace std;
using namespace __gnu_pbds;
typedef tree<int, null_type, less<int>, rb_tree_tag, tree_order_statistics_node_update> pbds;
#define getar(ar,n) for(ll i=0;i<n;++i) cin>>ar[i]
#define show(n) cout<<n<<'\n'
#define all(v) v.begin(), v.end()
#define br cout<<"\n"
#define pb push_back
#define nl '\n'
#define yes cout<<"YES\n"
#define no cout<<"NO\n"
#define ret return
#define ll long long
#define ld long double
#define sza(x) ((int)x.size())
const int mxN = 5000;
const ll INF = 1e9;
vector<pair<int,int>> adj[mxN];
vector<bool> exitt(mxN,0),cantgo(mxN,0);
int dist[mxN];
void dfs(int u=0,int par=-1){
if(exitt[u]) return;
pair<ll,ll> p={-1,INF};// node with min dist
for(auto it:adj[u]){
if(it.first!=par){
dfs(it.first,u);
if(p.second>it.second+dist[it.first]){
p.second=it.second+dist[it.first];
p.first=it.first;
}
}
}
cantgo[p.first]=1;
dist[u]=p.second;
}
int solN(int u=0,int par=-1){
if(exitt[u]) return 0;
int ans=INF;
for(auto it:adj[u]){
if(it.first!=par&&!cantgo[it.first]){
ans=min(ans,it.second+solN(it.first,u));
}
}
return ans;
}
int travel_plan(int n,int m,int r[][2],int l[],int k,int p[]){
for(int i=0;i<m;++i){
ll u=r[i][0],v=r[i][1],w=l[i];
adj[u].pb({v,w});
adj[v].pb({u,w});
}
for(int i=0;i<k;++i) exitt[p[i]]=1;
dfs();
return solN();
}
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