제출 #1082072

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
1082072		Boas	가장 긴 여행 (IOI23_longesttrip)	C++17	15 / 100	222 ms	3492 KiB

longesttrip

#include "longesttrip.h"

#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
using namespace std;
using namespace __gnu_pbds;

template <typename T1, typename T2>
using indexed_map = tree<T1, T2, less<T1>, rb_tree_tag, tree_order_statistics_node_update>;
template <typename T>
using indexed_set = indexed_map<T, null_type>;

#define loop(x, i) for (int i = 0; i < (x); i++)
#define loop1(x, i) for (int i = 1; i <= (x); i++)
#define rev(x, i) for (int i = (int)(x) - 1; i >= 0; i--)
#define itloop(x) for (auto it = begin(x); x != end(x); it++)
#define itrev(x) for (auto it = rbegin(x); x != rend(x); it++)
#define INF32 ((int32_t)(2e9 + 1))
#define ALL(x) begin(x), end(x)
#define RALL(x) rbegin(x), rend(x)
#define removeIn(x, l) l.erase(find(ALL(l), x))
#define pb push_back
#define sz(x) (int)(x).size()
#define F first
#define S second
#define var const auto &
#define foreach(l) for (var e : l)

typedef int8_t i8;
typedef int16_t i16;
typedef int32_t i32;
typedef int64_t i64;
typedef pair<int, int> ii;
typedef tuple<int, int, int> iii;
typedef tuple<int, int, int, int> iiii;
typedef vector<int> vi;
typedef vector<i32> vi32;
typedef vector<vi> vvi;
typedef vector<vvi> vvvi;
typedef vector<vi32> vvi32;
typedef vector<ii> vii;
typedef vector<iii> viii;
typedef vector<vii> vvii;
typedef vector<viii> vviii;
typedef set<int> si;
typedef set<ii> sii;
typedef set<iii> siii;
typedef vector<si> vsi;
typedef vector<sii> vsii;
typedef vector<vsi> vvsi;
typedef vector<string> vstr;
typedef vector<vector<string>> vvstr;
typedef vector<bool> vb;
typedef vector<vb> vvb;

vi longest_trip(int N, int D)
{
    if (D >= 2)
    {
        vi res(N);
        iota(ALL(res), 0);
        if (D == 3)
        {
            return res;
        }
        si resterend;
        loop1(N - 1, i) resterend.insert(res[i]);
        loop1(N - 1, i)
        {
            auto it = resterend.begin();
            if (are_connected({res[i - 1]}, {*it}))
            {
                res[i] = *it;
                resterend.erase(it);
            }
            else
            {
                if (resterend.size() == 1)
                {
                    res.insert(res.begin(), *it);
                    res.pop_back();
                    return res;
                }
                res[i] = *next(it);
                resterend.erase(next(it));
            }
        }
        return res;
    }
    else
    {
        vsi adj(N);
        for (int i = 0; i < N; i++)
        {
            for (int j = i + 1; j < N; j++)
            {
                if (are_connected({i}, {j}))
                {
                    adj[i].insert(j);
                    adj[j].insert(i);
                }
            }
        }
        if (N <= 4)
        {
            vb vis(N);
            ii furthest;
            vi route;
            vi bestRoute;
            auto dfs = [&](auto &&self, int i, int d) -> ii
            {
                ii maxD = {d, i};
                if (maxD > furthest)
                {
                    furthest = max(furthest, maxD);
                }
                vis[i] = 1;
                for (int j : adj[i])
                {
                    if (!vis[j])
                        maxD = max(maxD, self(self, j, d + 1));
                }
                if (maxD == furthest)
                {
                    route.pb(i);
                    if (sz(route) > sz(bestRoute))
                        bestRoute = route;
                }
                return maxD;
            };
            loop(N, i)
            {
                vis = vb(N);
                route.clear();
                dfs(dfs, i, 0);
            }
            return bestRoute;
        }
        si clique1, clique2;
        loop(N, i)
        {
            if (!clique1.empty())
                break;
            loop(N, j)
            {
                if (!clique1.empty())
                    break;
                loop(N, k)
                {
                    if (!clique1.empty())
                        break;
                    if (adj[i].count(j) && adj[j].count(k) && adj[k].count(i))
                    {
                        if (clique1.empty())
                        {
                            clique1 = {i, j, k};
                        }
                    }
                }
            }
        }
        loop(N, i)
        {
            if (clique1.count(i))
                continue;
            bool val = 1;
            for (int j : clique1)
            {
                if (!adj[j].count(i))
                    val = 0;
            }
            if (val)
                clique1.insert(i);
            else
                clique2.insert(i);
        }
        ii bridge;
        for (int i : clique1)
        {
            for (int j : adj[i])
            {
                if (clique2.count(j))
                {
                    bridge = {i, j};
                    break;
                }
            }
        }
        vi res;
        for (int i : clique1)
        {
            if (i != bridge.F)
                res.pb(i);
        }
        res.pb(bridge.F);
        res.pb(bridge.S);
        for (int i : clique2)
        {
            if (i != bridge.S)
                res.pb(i);
        }
        return res;
    }
    return {};
}

• Subtask 0: 0 / 0
• Subtask 1: 5 / 5
• Subtask 2: 10 / 10
• Subtask 3: 0 / 25
• Subtask 4: 0 / 60