제출 #108150

#제출 시각아이디문제언어결과실행 시간메모리
108150RockyB수열 (APIO14_sequence)C++11
100 / 100
523 ms82456 KiB
/// In The Name Of God #pragma GCC optimize("Ofast") #pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native") #include <bits/stdc++.h> #define f first #define s second #define pb push_back #define pp pop_back #define mp make_pair #define sz(x) (int)x.size() #define sqr(x) ((x) * 1ll * (x)) #define all(x) x.begin(), x.end() #define Kazakhstan ios_base :: sync_with_stdio(0), cin.tie(0), cout.tie(0); #define nl '\n' #define ioi exit(0); typedef long long ll; typedef long double ld; typedef unsigned long long ull; const int N = (int)1e5 + 7; const int inf = (int)1e9 + 7; const int mod = (int)1e9 + 7; const ll linf = (ll)1e18 + 7; const int dx[] = {-1, 0, 1, 0, 1, -1, -1, 1}; const int dy[] = {0, 1, 0, -1, 1, -1, 1, -1}; using namespace std; int get_int() { char x = getchar(); while (!isdigit(x)) x = getchar(); int res = 0; while (isdigit(x)) res = res * 10 + x - '0', x = getchar(); return res; } void out(int x) { if (x > 9) out(x / 10); putchar(x % 10 + '0'); } struct line { int k, id; ll b; line() {} line(int k, ll b, int id) : k(k), b(b), id(id) {} ll get(int x) { return (ll)k * x + b; } }; struct cht { int ptr, sz; line v[N]; inline double inter(line &a, line &b) { return (b.b - a.b) / (double)(a.k - b.k); } inline void add(line x) { /*int l = 2, r = sz, res = sz; while (l <= r) { int mid = l + r >> 1; if (inter(v[mid - 1], x) <= inter(v[mid - 1], v[mid])) res = mid - 1, r = mid - 1; else l = mid + 1; } sz = res;*/ while (sz > 1 && inter(v[sz - 1], x) <= inter(v[sz - 1], v[sz])) --sz; v[++sz] = x; } inline line get(ll x) { ptr = min(ptr, sz); while (ptr < sz && v[ptr].get(x) <= v[ptr + 1].get(x)) ptr++; return v[ptr]; } void clear() { sz = 0; ptr = 1; } } t; int n, k; int a[N], s[N], p[N]; int now; ll dp[2][N]; int opt[201][N]; bool upd(ll &x, ll y) { if (x < y) { x = y; return 1; } return 0; } int main() { #ifdef IOI2018 freopen ("in.txt", "r", stdin); #endif n = get_int(), k = get_int(); for (int i = 1; i <= n; i++) { a[i] = get_int(); s[i] = a[i]; p[i] = p[i - 1] + a[i]; } for (int i = n; i >= 1; i--) { s[i] += s[i + 1]; } for (int i = 1, p = 0; i <= n; i++) { p += a[i]; dp[now][i] = (ll)p * s[i + 1]; } for (int o = 2; o <= k; o++) { t.clear(); int nxt = now ^ 1; for (int i = o - 1; i <= n; i++) { t.add({p[i - 1], dp[now][i - 1], i}); line res = t.get(-s[i + 1]); opt[o][i] = res.id; dp[nxt][i] = res.get(-s[i + 1]) + (ll)p[i] * s[i + 1]; } now ^= 1; } ll ans = -linf; int ptr = -1; for (int i = 1; i < n; i++) { if (upd(ans, dp[now][i])) { ptr = i; } } printf ("%lld\n", ans); vector <int> res; for (int i = k; i >= 1; i--) { res.pb(ptr); ptr = opt[i][ptr] - 1; } reverse(all(res)); for (auto it : res) { out(it); putchar(' '); } ioi }

컴파일 시 표준 에러 (stderr) 메시지

sequence.cpp: In constructor 'line::line(int, ll, int)':
sequence.cpp:52:5: warning: 'line::b' will be initialized after [-Wreorder]
  ll b;
     ^
sequence.cpp:51:9: warning:   'int line::id' [-Wreorder]
  int k, id;
         ^~
sequence.cpp:54:2: warning:   when initialized here [-Wreorder]
  line(int k, ll b, int id) : k(k), b(b), id(id) {}
  ^~~~
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