이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include "soccer.h"
#include <bits/stdc++.h>
using namespace std;
#define pii array<int, 2>
vector<int> hlp(vector<int> &height) {
stack<pii> s;
s.push({height[0], 1});
int ar = height[0];
vector<int> ret(height.size());
ret[0] = ar;
for (int i=1;i<(int)height.size();i++) {
int cnt=1;
while (s.size() && height[i] <= s.top()[0]) {
auto [he, nm] = s.top();s.pop();
ar -= he * nm;
cnt += nm;
}
ar += cnt * height[i];
s.push({height[i], cnt});
ret[i] = ar;
}
return ret;
}
int calc(vector<int> &height) {
vector<int> v1 = hlp(height);
reverse(height.begin(), height.end());
vector<int> v2 = hlp(height);
reverse(height.begin(), height.end());
int n = (int)height.size();
int mx = 0;
reverse(v2.begin(), v2.end());
for (int i=0;i<n;i++) {
mx = max(mx, v1[i]+v2[i]-height[i]);
}
return mx;
}
int biggest_stadium(int N, std::vector<std::vector<int>> F) {
vector<vector<int>> up(N, vector<int>(N, 0));
vector<vector<int>> dw = up, lf = up, rt = up;
for (int i=0;i<N;i++) {
if (F[i][0] == 0) {
lf[i][0] = 1;
}
for (int j=1;j<N;j++) {
if (F[i][j] == 1) lf[i][j] = 0;
else lf[i][j] = lf[i][j-1] + 1;
}
if (F[i][N-1] == 0) rt[i][N-1] = 1;
for (int j=N-2;j>=0;j--) {
if (F[i][j] == 1) rt[i][j] = 0;
else rt[i][j] = rt[i][j+1]+1;
}
}
for (int j=0;j<N;j++) {
if (F[0][j] == 0) up[0][j] = 1;
for (int i=1;i<N;i++) {
up[i][j] = up[i-1][j]+1;
if (F[i][j] == 1) up[i][j]=0;
}
if (F[N-1][j] == 0) dw[N-1][j]=1;
for (int i=N-2;i>=0;i--) {
dw[i][j] = dw[i+1][j]+1;
if (F[i][j] == 1) dw[i][j]=0;
}
}
// for (int i=0;i<N;i++) {
// for (int j=0;j<N;j++) {
// cout << dw[i][j] << " ";
// }
// cout << "\n";
// }
// cout << "here " << endl;
int ans = 0;
for (int i=0;i<N;i++) {
for (int j=0;j<N;j++) {
if (F[i][j] == 1) continue;
int k = j;
vector<int> f1, f2;
for (;k<N&&F[i][k]!=1;k++) {
f1.push_back(up[i][k]);
f2.push_back(dw[i][k]);
}
ans = max(ans, max(calc(f1), calc(f2)));
j = k-1;
}
}
for (int j=0;j<N;j++) {
for (int i=0;i<N;i++) {
if (F[i][j] == 1) continue;
int k = i;
vector<int> f1, f2;
for (;k<N&&F[k][j]!=1;k++) {
f1.push_back(rt[k][j]);
f2.push_back(lf[k][j]);
}
ans = max(ans, max(calc(f1), calc(f2)));
i = k-1;
}
}
return ans;
}
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