| # | Time | Username | Problem | Language | Result | Execution time | Memory | 
|---|---|---|---|---|---|---|---|
| 1079802 | _rain_ | Crocodile's Underground City (IOI11_crocodile) | C++14 | 0 ms | 0 KiB | 
This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include<bits/stdc++.h>
using namespace std;
#define ll long long
#define fixbug false
void SETIO(string name = ""){
    if (name=="") return ;
    freopen((name+".inp").c_str(),"r",stdin);
    freopen((name+".out").c_str(),"w",stdout);
    return;
}
//... READ INPUT
    const int maxn = 50000;
    const int maxm = 10000000;
    static int R[maxm+2][2];
    static int L[maxn+2];
    static int P[maxn+2];
    int n , m , k;
vector<pair<int,int>> g[maxn+2];
ll d[maxn+2][2];
bool ex[maxn+2];
#define ii pair<ll,int>
#define fi first
#define se second
int travel(int n , int m , int R[][2] , int L[] , int k , int P[]){
    for (int i = 0; i < m; ++i) {
        g[R[i][0]].push_back({R[i][1] , L[i]});
        g[R[i][1]].push_back({R[i][0] , L[i]});
        if (fixbug){
            cout << R[i][0] << ' ' << R[i][1] << ' ' << L[i] << '\n';
        }
    }
    priority_queue<ii,vector<ii>,greater<ii>> q;
    memset(d,0x3f,sizeof d);
    ll ans = d[0][0];
    for (int i = 0 ; i < k; ++i){
        d[P[i]][0] = d[P[i]][1] = 0;
        q.push({0 , P[i]});
    }
    while (q.size()){
        int u = q.top().second; ll cost = q.top().first;
        q.pop();
        if (cost != d[u][0]) continue;
        if (fixbug){
            cout << "(DEBUG)\n";
            cout << u << ' ' << cost << "\n";
        }
        for (auto & x : g[u]){
            int v = x.first , w = x.second;
            if (d[v][0] > cost + w){
                d[v][0] = cost + w;
                if (d[v][1] > d[v][0]) swap(d[v][1] , d[v][0]);
                q.push({d[v][0] , v});
            }
        }
    }
    if (fixbug){
        cout << ans << '\n';
        for (int i = 0; i < n; ++i) cout << d[i][0] << '\n';
    }
    return d[0][0];
}
