Submission #1079340

#	Time	Username	Problem	Language	Result	Execution time	Memory
1079340		ArthuroWich	Catfish Farm (IOI22_fish)	C++17	0 / 100	1070 ms	2097152 KiB

fish

#include "fish.h"
#include<bits/stdc++.h>
using namespace std;
#define int long long int
int max_weights(int32_t N, int32_t M, vector<int32_t> X, vector<int32_t> Y, vector<int32_t> W) {
    int n = N, m = M;
    vector<vector<int>> c(n+1, vector<int>(n+1, 0));
    vector<vector<vector<int>>> dp(n+1, vector<vector<int>>(n+1, vector<int>(2, 0))); // 0 is increasing, 1 is decreasing, increasing can go to decreasing, decreasing cant go to increasing if next to eachother
    for (int i = 0; i < m; i++) {
        c[Y[i]+1][X[i]] = W[i];
    }
    for (int j = 1; j < n; j++) {
        int v = 0;
        dp[0][j][0] = max(dp[0][j][0], dp[0][j-1][0]);
        for (int i = 1; i <= n; i++) {
            v += c[i][j];
            dp[0][j][0] = max(dp[0][j][0], dp[i][j-1][0]+v);
            dp[0][j][0] = max(dp[0][j][0], dp[i][j-1][1]+v);
        }
        for (int i = 1; i <= n; i++) {
            for (int a = i; a <= n; a++) {
                v = 0;
                for (int b = i+1; b <= a; b++) {
                    v += c[b][j];
                }
                dp[i][j][1] = max(dp[i][j][1], dp[a][j-1][0]+v);
                dp[i][j][1] = max(dp[i][j][1], dp[a][j-1][1]+v);
            } 
            for (int a = 1; a <= i; a++) {
                v = 0;
                for (int b = a+1; b <= i; b++) {
                    v += c[b][j-1];
                }
                dp[i][j][0] = max(dp[i][j][0], dp[a][j-1][0]+v);
            } 
        }
        if (j == 1) {
            v = 0;
            for (int i = 1; i <= n; i++) {
                v += c[i][j-1];
                dp[i][j][0] = max(dp[i][j][0], dp[0][j-1][0]+v);
                dp[i][j][1] = max(dp[i][j][1], dp[0][j-1][0]+v);
            }
        }
        if (j-2 >= 0) {
            v = 0;
            for (int i = 1; i <= n; i++) {
                v += c[i][j-1];
                dp[i][j][0] = max(dp[i][j][0], dp[0][j-2][0]+v);
                dp[i][j][1] = max(dp[i][j][1], dp[0][j-2][0]+v);
            }
            for (int i = 1; i <= n; i++) {
                v = 0;
                for (int h = 1; h <= i; h++) {
                    v += c[h][j-1];
                }
                for (int h = 1; h <= i; h++) {
                    dp[i][j][0] = max(dp[i][j][0], dp[h][j-2][0]+v);
                    dp[i][j][0] = max(dp[i][j][0], dp[h][j-2][1]+v);
                    dp[i][j][1] = max(dp[i][j][1], dp[h][j-2][0]+v);
                    dp[i][j][1] = max(dp[i][j][1], dp[h][j-2][1]+v);
                }
                //for (int h = i+1; h < 9; h++) {
                //    v += c[h][j];
                //    dp[i][j][0] = max(dp[i][j][0], dp[h][j-2][0]+v);
                //    dp[i][j][0] = max(dp[i][j][0], dp[h][j-2][1]+v);
                //    dp[i][j][1] = max(dp[i][j][1], dp[h][j-2][0]+v);
                //    dp[i][j][1] = max(dp[i][j][1], dp[h][j-2][1]+v);
                //}
            }
        }
    }
    int ans = 0;
    for (int i = 0; i <= n; i++) {
        ans = max(ans, dp[i][n-1][0]);
        ans = max(ans, dp[i][n-1][1]);
    }
    return ans;
}

• Subtask 1: 0 / 3
• Subtask 2: 0 / 6
• Subtask 3: 0 / 9
• Subtask 4: 0 / 14
• Subtask 5: 0 / 21
• Subtask 6: 0 / 17
• Subtask 7: 0 / 14
• Subtask 8: 0 / 16