Submission #1078665

#TimeUsernameProblemLanguageResultExecution timeMemory
1078665doducanhExamination (JOI19_examination)C++14
100 / 100
2250 ms169064 KiB
///breaker
#pragma GCC optimize("O3,unroll-loops")
#pragma GCC target("avx")
#include<bits/stdc++.h>
using namespace std;
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;

#define ordered_set tree<pair<int,int>, null_type,less<pair<int,int> >, rb_tree_tag,tree_order_statistics_node_update>

#define ll long long
#define fi first
#define se second
#define ii pair<int,int>
#define mp make_pair
#define in(x) freopen(x,"r",stdin)
#define out(x) freopen(x,"w",stdout)
#define bit(x,i) ((x>>i)&1)
#define lc (id<<1)
#define rc ((id<<1)^1)
const int maxn=1e5+7;
const int sz=350;
struct fenwick
{
    vector <int> fen;
    int n;
    fenwick(int _n=1e5)
    {
        n=_n;
        fen.assign(n+5,0);
    }
    void add(int pos)
    {
        for(;pos>0;pos-=pos&-pos) fen[pos]++;
        return;
    }
    int get(int pos)
    {
        if (!pos) return 0;
        int ans=0;
        for(;pos<=n;pos+=pos&-pos) ans+=fen[pos];
        return ans;
    }
}t[sz+3];
struct Data
{
    int x,y,z,id;
};
int n,q;
Data a[maxn];
Data qu[maxn];
int ans[maxn];
ordered_set s[2*maxn];
vector<int>vx;
vector<int>vy;
int pos(int x,vector<int>&v)
{
    return lower_bound(v.begin(),v.end(),x)-v.begin()+1;
}
bool cmp(Data &a,Data &b)
{
    return a.z>b.z;
}
void sol(void){
    cin>>n>>q;
    for(int i=1;i<=n;i++){
        cin>>a[i].x>>a[i].y;
        vx.push_back(a[i].x);
        vy.push_back(a[i].y);
        a[i].z=a[i].x+a[i].y;
    }
    for(int i=1;i<=q;i++){
        cin>>qu[i].x>>qu[i].y>>qu[i].z;
        qu[i].id=i;
    }
    sort(vx.begin(),vx.end());
    sort(vy.begin(),vy.end());
    vx.erase(unique(vx.begin(),vx.end()),vx.end());
    vy.erase(unique(vy.begin(),vy.end()),vy.end());
    sort(a+1,a+n+1,cmp);
    sort(qu+1,qu+q+1,cmp);
    int l=1;
    for(int i=1;i<=n;i++){
        int pos1=pos(a[i].x,vx);
        int pos2=pos(a[i].y,vy);
        t[(pos1-1)/sz].add(pos2);
        s[pos1].insert({pos2,i});
        if(i<n&&a[i].z==a[i+1].z)continue;
        while(l<=q&&(i==n||qu[l].z>a[i+1].z)){
            if(qu[l].z>a[i].z){
                l++;
                continue;
            }
            pos1=pos(qu[l].x,vx);
            pos2=pos(qu[l].y,vy);
            int tmp=0;
            for(int block=(pos1-1)/sz+1; block<=(vx.size()-1)/sz; block++)tmp+=t[block].get(pos2);
            for(int els=pos1; els<=((pos1-1)/sz+1)*sz; els++)tmp+=s[els].size()-s[els].order_of_key({pos2,0});
            ans[qu[l].id]=tmp;
            l++;
        }
    }
    for(int i=1;i<=q;i++){
        cout<<ans[i]<<"\n";
    }
    return;
}
signed main(void)
{
    ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0);
    int t=1;
    while(t--){
        sol();
    }
    // you should actually read the stuff at the bottom
    return 0;
}
/* stuff you should look for
 * int overflow, array bounds
 * special cases (n=1?)
 * do smth instead of nothing and stay organized
 * WRITE STUFF DOWN
 * DON'T GET STUCK ON ONE APPROACH
 */

Compilation message (stderr)

examination.cpp: In function 'void sol()':
examination.cpp:98:47: warning: comparison of integer expressions of different signedness: 'int' and 'std::vector<int>::size_type' {aka 'long unsigned int'} [-Wsign-compare]
   98 |             for(int block=(pos1-1)/sz+1; block<=(vx.size()-1)/sz; block++)tmp+=t[block].get(pos2);
      |                                          ~~~~~^~~~~~~~~~~~~~~~~~
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