oj.uz

답안 #1078305

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
1078305 2024-08-27T15:06:39 Z c2zi6 참나무 (IOI23_beechtree) C++17
14 / 100
 53 ms 20112 KB 
#define _USE_MATH_DEFINES
#include <bits/stdc++.h>
#define ff first
#define ss second
#define pb push_back
#define all(a) (a).begin(), (a).end()
#define replr(i, a, b) for (int i = int(a); i <= int(b); ++i)
#define reprl(i, a, b) for (int i = int(a); i >= int(b); --i)
#define rep(i, n) for (int i = 0; i < int(n); ++i)
#define mkp(a, b) make_pair(a, b)
using namespace std;
typedef long long ll;
typedef long double ld;
typedef pair<int, int> PII;
typedef vector<int> VI;
typedef vector<PII> VPI;
typedef vector<VI> VVI;
typedef vector<VVI> VVVI;
typedef vector<VPI> VVPI;
typedef pair<ll, ll> PLL;
typedef vector<ll> VL;
typedef vector<PLL> VPL;
typedef vector<VL> VVL;
typedef vector<VVL> VVVL;
typedef vector<VPL> VVPL;
template<class T> T setmax(T& a, T b) {if (a < b) return a = b; return a;}
template<class T> T setmin(T& a, T b) {if (a < b) return a; return a = b;}
#include <ext/pb_ds/assoc_container.hpp>
using namespace __gnu_pbds;
template<class T>
using indset = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
#include "beechtree.h"

namespace TEST2 {
    bool check(VI par) {
        rep(i, par.size()) if (par[i] != i-1) return false;
        return true;
    }
    VI solve(VI color) {
        int n = color.size();
        VI answer(n);
        bool ans = true;
        reprl(i, n-1, 0) {
            answer[i] = ans;
            if (color[i] != color[n-1]) ans = false;
        }
        return answer;
    }
};
namespace TEST3 {
    bool check(VI par) {
        rep(i, par.size()) if (i) {
            if (par[i] != 0 && par[par[i]] != 0) return false;
        }
        return true;
    }
    int n;
    VVI gp;
    VI par;
    VI color;
    set<int> scol(int u) {
        set<int> ret;
        for (int u : gp[u]) ret.insert(color[u]);
        return ret;
    }
    VI solve(int N_ARG, VVI GP_ARG, VI PAR_ARG, VI COLOR_ARG) {
        n = N_ARG;
        gp = GP_ARG;
        par = PAR_ARG;
        color = COLOR_ARG;
        VI answer(n, 1);
        answer[0] = false;
        replr(u, 1, n-1) {
            if (scol(u).size() != gp[u].size()) answer[u] = false;
        }
        set<int> allowed = scol(0);
        if (allowed.size() != gp[0].size()) {
            return answer;
        }
        replr(u, 1, n-1) if (allowed.count(color[u]) == 0) {
            return answer;
        }
        map<int, VI> cnt;
        for (int u : gp[0]) {
            for (int v : gp[u]) {
                cnt[color[v]].pb(u);
            }
        }
        VVI a;
        for (auto& p : cnt) a.pb(p.ss);
        sort(all(a), [&](const VI& a, const VI& b){return a.size() < b.size();});
        VI construct;
        VI ka(n);
        for (VI& vec : a) {
            for (int x : vec) {
                if (ka[x]) continue;
                construct.pb(x);
                ka[x] = true;
            }
            if (construct.size() > vec.size()) {
                return answer;
            }
        }
        answer[0] = true;
        return answer;
    }
};
namespace TEST4 {
    int n;
    VVI gp;
    VI par;
    VI color;
    set<int> scol(int u) {
        set<int> ret;
        for (int u : gp[u]) ret.insert(color[u]);
        return ret;
    }
    bool getans(int u) {
        int mec = -1;
        set<int> my = scol(u);
        if (my.size() != gp[u].size()) return false;
        for (int v : gp[u]) {
            if (gp[v].size()) {
                if (mec == -1) mec = v;
                else return false;
            }
        }
        if (mec == -1) return true;
        // mec-i guyner@ pti exnin u-i guyneri entabazmutyun
        for (int v : gp[mec]) {
            if (gp[v].size()) return false;
            if (my.count(color[v]) == 0) return false;
        }
        return true;
    }
    VI solve(int N_ARG, VVI GP_ARG, VI PAR_ARG, VI COLOR_ARG) {
        n = N_ARG;
        gp = GP_ARG;
        par = PAR_ARG;
        color = COLOR_ARG;
        VI ans(n);
        rep(u, n) ans[u] = getans(u);
        return ans;
    }
};

int n;
VVI gp;
VI par;
VI color;

VI answer;
VI dfs(int u = 0) {
    VI ret;
    for (int v : gp[u]) {
        VI his = dfs(v);
        for (int x : his) ret.pb(x);
    }
    bool ardyoq = false;
    ret.pb(u);
    sort(all(ret));
    do {
        if (ret[0] != u) continue;
            VI prev;
            rep(i, ret.size()) if (i) {
                int u = ret[i];
                int cnt = 0;
                for (int v : prev) if (color[v] == color[u]) cnt++;
                if (ret[cnt] != par[u]) goto vat;
                prev.pb(u);
            }
        ardyoq = true;
        break;
        vat:;
    } while (next_permutation(all(ret)));
    answer[u] = ardyoq;
    return ret;
}

VI beechtree(int N, int M, VI P, VI C) {
    n = N;
    par = P;
    color = C;
    gp = VVI(n);
    rep(u, n) if (par[u] != -1) gp[par[u]].pb(u);

    if (TEST2::check(P)) return TEST2::solve(C);
    if (n > 8) {
        if (TEST3::check(P)) return TEST3::solve(n, gp, par, color);
        return TEST4::solve(n, gp, par, color);
    }

    answer = VI(n);
    dfs();

    VI ans1 = TEST4::solve(n, gp, par, color);
    for (int x : ans1) cout << x << " "; cout << endl;
    return answer;
}

Compilation message

beechtree.cpp: In function 'VI beechtree(int, int, VI, VI)':
beechtree.cpp:197:5: warning: this 'for' clause does not guard... [-Wmisleading-indentation]
  197 |     for (int x : ans1) cout << x << " "; cout << endl;
      |     ^~~
beechtree.cpp:197:42: note: ...this statement, but the latter is misleadingly indented as if it were guarded by the 'for'
  197 |     for (int x : ans1) cout << x << " "; cout << endl;
      |                                          ^~~~

Subtask #0
0.0 / 0.0

# 결과 실행 시간 메모리 Grader output
1 Incorrect 1 ms 344 KB Possible tampering with the output
2 Halted 0 ms 0 KB -

Subtask #1
0.0 / 9.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 348 KB Output is correct
2 Correct 1 ms 376 KB Output is correct
3 Correct 1 ms 440 KB Output is correct
4 Correct 0 ms 348 KB Output is correct
5 Correct 0 ms 348 KB Output is correct
6 Correct 0 ms 348 KB Output is correct
7 Incorrect 0 ms 348 KB Possible tampering with the output
8 Halted 0 ms 0 KB -

Subtask #2
5.0 / 5.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 348 KB Output is correct
2 Correct 1 ms 376 KB Output is correct
3 Correct 1 ms 440 KB Output is correct
4 Correct 0 ms 348 KB Output is correct
5 Correct 0 ms 348 KB Output is correct
6 Correct 0 ms 348 KB Output is correct
7 Correct 50 ms 19776 KB Output is correct
8 Correct 53 ms 19872 KB Output is correct
9 Correct 0 ms 344 KB Output is correct
10 Correct 0 ms 344 KB Output is correct
11 Correct 1 ms 344 KB Output is correct
12 Correct 1 ms 348 KB Output is correct
13 Correct 1 ms 604 KB Output is correct
14 Correct 1 ms 604 KB Output is correct
15 Correct 1 ms 604 KB Output is correct
16 Correct 1 ms 604 KB Output is correct
17 Correct 53 ms 19788 KB Output is correct
18 Correct 51 ms 20044 KB Output is correct
19 Correct 53 ms 20044 KB Output is correct
20 Correct 53 ms 20112 KB Output is correct

Subtask #3
9.0 / 9.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 348 KB Output is correct
2 Correct 1 ms 348 KB Output is correct
3 Correct 0 ms 348 KB Output is correct
4 Correct 1 ms 348 KB Output is correct
5 Correct 0 ms 348 KB Output is correct
6 Correct 0 ms 348 KB Output is correct
7 Correct 0 ms 600 KB Output is correct
8 Correct 1 ms 348 KB Output is correct
9 Correct 0 ms 348 KB Output is correct
10 Correct 0 ms 348 KB Output is correct
11 Correct 1 ms 604 KB Output is correct
12 Correct 1 ms 348 KB Output is correct
13 Correct 1 ms 348 KB Output is correct
14 Correct 1 ms 348 KB Output is correct
15 Correct 46 ms 16060 KB Output is correct
16 Correct 34 ms 13748 KB Output is correct
17 Correct 34 ms 13884 KB Output is correct
18 Correct 43 ms 15812 KB Output is correct

Subtask #4
0.0 / 8.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 348 KB Output is correct
2 Correct 1 ms 376 KB Output is correct
3 Incorrect 0 ms 348 KB Possible tampering with the output
4 Halted 0 ms 0 KB -

Subtask #5
0.0 / 14.0

# 결과 실행 시간 메모리 Grader output
1 Incorrect 1 ms 344 KB Possible tampering with the output
2 Halted 0 ms 0 KB -

Subtask #6
0.0 / 14.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 348 KB Output is correct
2 Correct 1 ms 376 KB Output is correct
3 Incorrect 0 ms 348 KB Possible tampering with the output
4 Halted 0 ms 0 KB -

Subtask #7
0.0 / 12.0

# 결과 실행 시간 메모리 Grader output
1 Incorrect 1 ms 344 KB Possible tampering with the output
2 Halted 0 ms 0 KB -

Subtask #8
0.0 / 17.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 348 KB Output is correct
2 Correct 1 ms 376 KB Output is correct
3 Incorrect 0 ms 348 KB Possible tampering with the output
4 Halted 0 ms 0 KB -

Subtask #9
0.0 / 12.0

# 결과 실행 시간 메모리 Grader output
1 Incorrect 1 ms 344 KB Possible tampering with the output
2 Halted 0 ms 0 KB -