이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef vector<ll> vii;
typedef pair<ll,ll> pii;
#define F first
#define S second
#define all(v) v.begin(),v.end()
#define pb push_back
const ll M=2e6+10;
const ll inf=2e18+10;
const ll mod=1e9+7;
ll n,m,a[M],cnt[M],cntb[40],ans[M];
int main() {
ios_base::sync_with_stdio(0),cin.tie(0);
cin>>n>>m;
for(int i=0;i<n;i++)
for(int j=0;j<m;j++) {
ll x;
cin>>x;
a[i]+=(x*(1<<j));
cntb[j]+=x;
}
for(int i=0;i<n;i++) {
for(int j=a[i];j<(1<<m);j++,j|=a[i]) {
cnt[j]++;
}
}
for(int i=0;i<(1<<m);i++)
ans[i]=-1;
for(int i=0;i<n;i++) {
ll res=0,x=0;
for(int j=0;j<m;j++) {
if(cntb[j]-bool(((1<<j)&a[i])>0)>n/2)
res++;
else if(cntb[j]-bool(((1<<j)&a[i])>0)==n/2) {
x+=(1<<j);
}
}
if(ans[x]>-1) {
cout<<ans[x]<<'\n';
continue;
}
ll res1=0;
for(int j=x;j>=0;j--) {
if(j<0)
break;
j&=x;
ll y=j+(((1<<m)-1)^x);
if((a[i]&y)==a[i])
cnt[y]--;
if(cnt[y]>0)
res1=max(res1,(ll)__builtin_popcountll(x)-__builtin_popcountll(j));
if((a[i]&y)==a[i])
cnt[y]++;
}
ans[x]=res1+res;
cout<<res1+res<<'\n';
}
}
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