제출 #1074991

#제출 시각아이디문제언어결과실행 시간메모리
1074991mickey080929추월 (IOI23_overtaking)C++17
100 / 100
1232 ms48000 KiB
#include "overtaking.h" #include <bits/stdc++.h> #pragma GCC optimize("O3") #pragma GCC optimize("Ofast") #pragma GCC optimize("unroll-loops") using namespace std; typedef long long ll; typedef long double ld; const ll inf = 4e18 + 10; struct Line{ ll a, b; ll id; }; bool cmp(Line l1, Line l2, ll x) { ll t1 = (x-l1.a) / l1.b, t2 = (x-l2.a) / l2.b; if (t1 == t2) return ((x-l1.a)-t1*l1.b) * l2.b < ((x-l2.a)-t2*l2.b) * l1.b; return t1 < t2; } struct Node{ ll l, r; Line line; }; struct LiChaoTree{ vector<Node> tree; void init() { tree.clear(); tree.push_back({-1, -1, {-inf, 1, -1}}); } void update(ll node, ll s, ll e, Line p) { Line lo = tree[node].line; Line hi = p; if (cmp(hi, lo, s)) swap(lo, hi); if (!cmp(hi, lo, e)) { tree[node].line = lo; return; } ll mid = (s + e) / 2; if (!cmp(hi, lo, mid)) { tree[node].line = lo; if (tree[node].r == -1) { tree[node].r = tree.size(); tree.push_back({-1, -1, {-inf, 1, -1}}); } update(tree[node].r, mid+1, e, hi); } else { tree[node].line = hi; if (tree[node].l == -1) { tree[node].l = tree.size(); tree.push_back({-1, -1, {-inf, 1, -1}}); } update(tree[node].l, s, mid, lo); } } Line query(ll node, ll s, ll e, ll x) { if (node == -1) return {-inf, 1, -1}; if (s == e) return tree[node].line; ll mid = (s + e) / 2; if (x <= mid) { Line t = query(tree[node].l, s, mid, x); if (cmp(t, tree[node].line, x)) return t; return tree[node].line; } Line t = query(tree[node].r, mid+1, e, x); if (cmp(t, tree[node].line, x)) return t; return tree[node].line; } }; LiChaoTree seg; LiChaoTree seg2[1010]; vector<ll> t1; int N, M; ll L, X; vector<ll> T, W, S; ll arr[1010][1010]; ll st[1010][1010]; void init(int _L, int _N, vector<ll> _T, vector<int> _W, int _X, int _M, vector<int> _S) { L = _L; X = _X; M = _M; for (int i=0; i<M; i++) { S.push_back(_S[i]); } for (int i=0; i<_N; i++) { if (_W[i] > X) { T.push_back(_T[i]); W.push_back(_W[i]); N ++; } } for (int i=0; i<N; i++) { arr[0][i] = T[i]; } for (int i=1; i<M; i++) { vector<tuple<ll,ll,ll>> id(N); for (ll j=0; j<N; j++) { id[j] = {arr[i-1][j], W[j], j}; } sort(id.begin(), id.end()); ll mx = 0; for (auto &[t1, t2, j] : id) { arr[i][j] = max(mx, arr[i-1][j] + W[j] * (S[i] - S[i-1])); mx = max(mx, arr[i][j]); } } for (int i=M-1; i>=0; i--) { vector<pair<ll,ll>> id(N); for (ll j=0; j<N; j++) { id[j] = {arr[i][j], j}; } sort(id.begin(), id.end()); seg.init(); for (auto &[_, j] : id) { if (j == id[0].second) { st[i][j] = arr[i][j] + (L - S[i]) * X; } else { ll cross = seg.query(0, 0, inf, arr[i][j]).id; assert(cross != -1); ll pos = S[i] + (arr[i][j] - arr[i][cross] + W[cross] - X - 1) / (W[cross] - X); if (pos > L) { st[i][j] = arr[i][j] + (L - S[i]) * X; } else { ll idx = lower_bound(S.begin(), S.end(), pos) - S.begin(); st[i][j] = st[idx][cross]; } } seg.update(0, 0, inf, {arr[i][j], W[j] - X, j}); } } vector<int> id(N); iota(id.begin(), id.end(), 0); sort(id.begin(), id.end(), [&] (int &u, int &v) { return T[u] < T[v]; }); for (int i=0; i<=N; i++) { seg2[i].init(); for (int j=0; j<i; j++) { seg2[i].update(0, 0, inf, {T[id[j]], W[id[j]] - X, id[j]}); } } t1 = T; sort(t1.begin(), t1.end()); return; } long long arrival_time(long long Y) { ll idx = lower_bound(t1.begin(), t1.end(), Y) - t1.begin(); if (idx == 0) return Y + X * L; ll cross = seg2[idx].query(0, 0, inf, Y).id; assert(cross != -1); ll pos = (Y - T[cross] + W[cross] - X - 1) / (W[cross] - X); if (pos > L) return Y + X * L; ll idx2 = lower_bound(S.begin(), S.end(), pos) - S.begin(); assert(st[idx2][cross] >= Y); return st[idx2][cross]; }
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