이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include "koala.h"
#include<bits/stdc++.h>
using namespace std;
int b[100],r[100];
int minValue(int n, int w) {
for(int i=0;i<n;i++){
b[i]=0;
}
b[0]=1;
playRound(b,r);
if(r[0]==2){
for(int i=1;i<n;i++){
if(r[i]==0)return i;
}
}
return 0;
}
int maxValue(int n, int w) {
bool ok[n];
memset(ok,1,n);
for(int i=1;i<=16;i<<=1){
if(i==8)i=11;
for(int j=0;j<n;j++){
if(ok[j]){
b[j]=i;
}else{
b[j]=0;
}
}
playRound(b,r);
int cnt=0;
for(int j=0;j<n;j++){
if(ok[j]){
if(i<r[j]){
cnt++;
}else{
ok[j]=0;
}
}
}
}
for(int i=0;i<n;i++)if(ok[i])return i;
return -1;
}
int trycnt(int d,int n){
for(int i=0;i<n;i++){
b[i]=0;
}
b[0]=b[1]=d;
playRound(b,r);
if((d<r[0])!=(d<r[1])){
if(d<r[0])return 0;
return 1;
}
if(d<r[0])return 2;
return 3;
}
int greaterValue(int n,int w) {
int res=trycnt(4,n);
if(res<2)return res;
if(res==2){
res=trycnt(6,n);
if(res<2)return res;
res=trycnt(9,n);
return res;
}
res=trycnt(2,n);
if(res<2)return res;
return !minValue(n,w);
}
void allValues(int N, int W, int *P) {
if (W == 2*N) {
// TODO: Implement Subtask 4 solution here.
// You may leave this block unmodified if you are not attempting this
// subtask.
} else {
// TODO: Implement Subtask 5 solution here.
// You may leave this block unmodified if you are not attempting this
// subtask.
}
}
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