Submission #1074557

#	Time	Username	Problem	Language	Result	Execution time	Memory
1074557		c2zi6	Digital Circuit (IOI22_circuit)	C++17	9 / 100	3020 ms	5048 KiB

circuit

#define _USE_MATH_DEFINES
#include <bits/stdc++.h>
#define ff first
#define ss second
#define pb push_back
#define all(a) (a).begin(), (a).end()
#define replr(i, a, b) for (int i = int(a); i <= int(b); ++i)
#define reprl(i, a, b) for (int i = int(a); i >= int(b); --i)
#define rep(i, n) for (int i = 0; i < int(n); ++i)
#define mkp(a, b) make_pair(a, b)
using namespace std;
typedef long long ll;
typedef long double ld;
typedef pair<int, int> PII;
typedef vector<int> VI;
typedef vector<PII> VPI;
typedef vector<VI> VVI;
typedef vector<VVI> VVVI;
typedef vector<VPI> VVPI;
typedef pair<ll, ll> PLL;
typedef vector<ll> VL;
typedef vector<PLL> VPL;
typedef vector<VL> VVL;
typedef vector<VVL> VVVL;
typedef vector<VPL> VVPL;
template<class T> T setmax(T& a, T b) {if (a < b) return a = b; return a;}
template<class T> T setmin(T& a, T b) {if (a < b) return a; return a = b;}
#include <ext/pb_ds/assoc_container.hpp>
using namespace __gnu_pbds;
template<class T>
using indset = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
#include "circuit.h"

const ll MOD = 1000002022;
bool test1;

int n;
VVI gp;
VI val;

void init(int N, int M, VI P, VI A) {
    test1 = (N == 1);
    n = N + M;
    gp = VVI(n);
    rep(u, n) if (u) gp[P[u]].pb(u);
    val = VI(n);
    rep(u, M) val[u+N] = A[u];
}

VL dpa; // sev
VL dpb; // spitak

void dfs(int u = 0, int p = -1) {
    if (gp[u].size() == 0) {
        if (val[u]) dpa[u] = 1;
        else dpb[u] = 1;
        return;
    }
    VL a, b;
    for (int v : gp[u]) if (v != p) {
        dfs(v);
        a.pb(dpa[v]);
        b.pb(dpb[v]);
    }
    dpa[u] = (2*a[0]*a[1]%MOD + a[0]*b[1]%MOD + b[0]*a[1]%MOD)%MOD;
    dpb[u] = (2*b[0]*b[1]%MOD + a[0]*b[1]%MOD + b[0]*a[1]%MOD)%MOD;

}

int count_ways(int L, int R) {
    replr(i, L, R) val[i] = !val[i];
    if (test1) {
        int sum = 0;
        for (int x : val) sum += x;
        return sum;
    }
    dpa = dpb = VL(n);
    dfs();
    /*rep(u, n) {*/
    /*    cout << u << ": " << dpa[u] << endl;*/
    /*}*/
    /*rep(u, n) cout << u << ": " << dpa[u] << endl;*/
    return dpa[0];
}

• Subtask 1: 2 / 2
• Subtask 2: 7 / 7
• Subtask 3: 0 / 9
• Subtask 4: 0 / 4
• Subtask 5: 0 / 12
• Subtask 6: 0 / 27
• Subtask 7: 0 / 28
• Subtask 8: 0 / 11