이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#define REP(a, b) for(int a = 0; a < b; a++)
#define FOR(i, a, b) for(int i = a; i <= b; i++)
#define mp make_pair
#define f first
#define s second
#define pb push_back
using namespace std;
typedef long long ll;
typedef pair<int, int> ii;
typedef pair<ll, ll> LL;
typedef vector<int> vi;
const ll INF = 1e9;
const ll MOD = 1e9 + 7;
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
//shuffle(permutation.begin(), permutation.end(), rng);
//uniform_int_distribution<int>(l, r)(rng);
const int MAXN = 105;
int n, L;
int A[MAXN];
int DP[MAXN][MAXN][2][2][10 * MAXN];
int rek(int pos, int nyak, int l, int r, int sum) {
if (sum > L) return 0;
if (pos == n) {
if (nyak == 0) return 1;
return 0;
}
int &ret = DP[pos][nyak][l][r][sum];
if (ret != -1) return ret;
int sek = 0;
if (pos) sek = sum + ((l + r + 2 * nyak) * (A[pos] - A[pos - 1]));
ret = 0;
if (pos == (n - 1)) {
ret = (ret + rek(pos + 1, nyak, 1, 1, sek)) % MOD;
return ret;
}
ret = (ret + rek(pos + 1, nyak, 1, r, sek)) % MOD;
ret = (ret + rek(pos + 1, nyak, l, 1, sek)) % MOD;
if (nyak) {
ll tmp = rek(pos + 1, nyak - 1, 1, r, sek);
tmp = tmp * nyak % MOD;
ret = (ret + tmp) % MOD;
tmp = rek(pos + 1, nyak - 1, l, 1, sek);
tmp = tmp * nyak % MOD;
ret = (ret + tmp) % MOD;
tmp = rek(pos + 1, nyak, l, r, sek);
tmp = tmp * nyak % MOD;
tmp = tmp * 2 % MOD;
ret = (ret + tmp) % MOD;
if (nyak >= 2) {
tmp = rek(pos + 1, nyak - 1, l, r, sek);
tmp = tmp * nyak % MOD;
tmp = tmp * (nyak - 1) % MOD;
ret = (ret + tmp) % MOD;
}
}
ret = (ret + rek(pos + 1, nyak + 1, l, r, sek));
return ret;
}
int main() {
//freopen("input.txt", "r", stdin);
//freopen("output.txt", "w", stdout);
ios::sync_with_stdio(0); cin.tie(0);
memset(DP, -1, sizeof DP);
cin >> n >> L;
REP(i, n) cin >> A[i];
sort(A, A + n);
cout << rek(0, 0, 0, 0, 0) << '\n';
}
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