Submission #1073349

#TimeUsernameProblemLanguageResultExecution timeMemory
1073349ProtonDecay314Text editor (CEOI24_editor)C++17
0 / 100
4059 ms1048576 KiB
#include<bits/stdc++.h>
using namespace std;
typedef int ll; // ! CAREFUL
typedef vector<ll> vll;
typedef vector<vll> vvll;
typedef vector<int> vi;
typedef vector<vi> vvi;
typedef pair<ll, ll> pll;
typedef pair<int, int> pi;
typedef vector<bool> vb;
#define fi first
#define se second
#define IOS cin.tie(nullptr); cout.tie(nullptr); ios_base::sync_with_stdio(false)
#define pb push_back

ll solve(ll n, ll sl, ll sc, ll el, ll ec, const vll& l) {
    vll prefl(n + 1, 0);

    for(ll i = 0; i < n; i++) {
        prefl[i + 1] = prefl[i] + l[i];
    }

    ll totn = prefl[n];

    vvll adj;

    for(ll i = 0; i < totn; i++) {
        vll adjr;
        adj.pb(adjr);
    }

    ll s = prefl[sl] + sc, e = prefl[el] + ec;

    for(ll li = 0; li < n; li++) {
        for(ll ci = 0; ci < l[li]; ci++) {
            ll ni = prefl[li] + ci;

            ll adji;

            // up
            if(li > 0) {
                adji = prefl[li - 1] + min(ci, l[li - 1] - 1);
                adj[ni].pb(adji);
            }

            // down
            if(li < n - 1) {
                adji = prefl[li + 1] + min(ci, l[li + 1] - 1);
                adj[ni].pb(adji);
            }

            // left
            if(li > 0 || ci > 0) {
                adji = ni - 1;
                adj[ni].pb(adji);
            }

            // right
            if(li < n - 1) {
                adji = ni + 1;
                adj[ni].pb(adji);
            }
        }
    }

    // Performing BFS
    vb vis(totn, false);

    queue<pll> q;

    q.push({s, 0});

    ll ans = 0;

    while(!q.empty()) {
        auto [i, dist] = q.front();

        if(vis[i]) continue;
        vis[i] = true;

        if(i == e) {
            ans = dist;
            break;
        }

        for(ll j : adj[i]) {
            q.push({j, dist + 1});
        }
    }

    return ans;
}

int main() {
    IOS;

    ll n;
    cin >> n;

    ll sl, sc;
    ll el, ec;
    cin >> sl >> sc;
    cin >> el >> ec;

    sl--; sc--;
    el--; ec--;

    vll l(n, 0);

    for(ll& lv : l) {
        cin >> lv;
        lv++; // ! WARNING, already added one
    }

    cout << solve(n, sl, sc, el, ec, l) << endl;
    
    return 0;
}
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