제출 #1072945

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
1072945		coolboy19521	힘 센 거북 (IZhO11_turtle)	C++17	10 / 100	2075 ms	2060 KiB

turtle

// Thanks Benq

#include "bits/stdc++.h"
#define ll long long

using namespace std;

const int sz = 1e6 + 6;
const int sm = 22;

vector<pair<int,int>> vp;
vector<int> ps;
int x[sz], y[sz];
ll wz[sm][sm];
ll dp[sm][sm];
bool sv[sz];

ll bpw(ll x, ll b, ll z) {
    ll r = 1;
    while (b) {
        if (b & 1)
            (r *= x) %= z;
        (x *= x) %= z;
        b >>= 1;
    }
    return r;
}

ll nck(ll n, ll k, ll z) {
    ll r = 1;
    for (ll i = 0; i < (ll) ps.size(); i ++) {
        ll p = ps[i], e = 0;
        if (p > n) break;
        for (ll c = p; c <= n; c *= p)
            e += n / c;
        for (ll c = p; c <= n; c *= p)
            e -= k / c;
        for (ll c = p; c <= n; c *= p)
            e -= (n - k) / c;
        (r *= bpw(p, e, z)) %= z;
    }
    return r;
}

ll gt(pair<int,int> f, pair<int,int> s, int z) {
    int xds = s.first - f.first;
    int yds = s.second - f.second;
    if (yds < 0) return 0;
    return nck(xds + yds, yds, z);
}

ll sb(ll a, ll b, ll z) {
    return (a + z - b) % z;
}

ll ml(ll a, ll b, ll z) {
    return a * b % z;
}

ll ad(ll a, ll b, ll z) {
    return (a + b) % z;
}

int main() {
    for (ll i = 2; i < sz; i ++) {
        if (sv[i]) continue;
        ps.push_back(i);
        sv[i] = true;
        for (ll j = i * i; j < sz; j += i)
            sv[j] = true;
    }

    ll n, m, k, t, z;
    cin >> n >> m >> k >> t >> z;

    for (int i = 0; i < k; i ++) {
        int x, y;
        cin >> x >> y;
        vp.push_back(make_pair(x, y));
    }

    vp.push_back(make_pair(0, 0));
    vp.push_back(make_pair(n, m));

    sort(begin(vp), end(vp));
    k = vp.size();

    for (int i = 1; i < k; i ++)
        for (int j = i - 1; 0 <= j; j --) {
            wz[j][i] = gt(vp[j], vp[i], z);
            for (int l = j + 1; l < i; l ++)
                wz[j][i] = sb(wz[j][i], ml(wz[j][l], gt(vp[k], vp[i], z), z), z);
        }

    dp[0][0] = 1;

    for (int i = 1; i < k; i ++)
        for (int j = 0; j < i; j ++)
            for (int l = 1; l <= t + 1; l ++)
                dp[i][l] = ad(dp[i][l], ml(dp[j][l - 1], wz[j][i], z), z);

    ll r = 0;

    for (int i = 1; i <= t + 1; i ++)
        r = ad(r, dp[k - 1][i], z);

    cout << r << '\n';
}

• Subtask 1: 10 / 100