제출 #1071911

#제출 시각아이디문제언어결과실행 시간메모리
1071911c2zi6수천개의 섬 (IOI22_islands)C++17
6.75 / 100
23 ms6564 KiB
#define _USE_MATH_DEFINES #include <bits/stdc++.h> #define ff first #define ss second #define pb push_back #define all(a) (a).begin(), (a).end() #define replr(i, a, b) for (int i = int(a); i <= int(b); ++i) #define reprl(i, a, b) for (int i = int(a); i >= int(b); --i) #define rep(i, n) for (int i = 0; i < int(n); ++i) #define mkp(a, b) make_pair(a, b) using namespace std; typedef long long ll; typedef long double ld; typedef pair<int, int> PII; typedef vector<int> VI; typedef vector<PII> VPI; typedef vector<VI> VVI; typedef vector<VVI> VVVI; typedef vector<VPI> VVPI; typedef pair<ll, ll> PLL; typedef vector<ll> VL; typedef vector<PLL> VPL; typedef vector<VL> VVL; typedef vector<VVL> VVVL; typedef vector<VPL> VVPL; template<class T> T setmax(T& a, T b) {if (a < b) return a = b; return a;} template<class T> T setmin(T& a, T b) {if (a < b) return a; return a = b;} #include <ext/pb_ds/assoc_container.hpp> using namespace __gnu_pbds; template<class T> using indset = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>; #include "islands.h" namespace GETPATH { VI vis; VVPI gp; VI order; bool dfs(int u, int e) { if (u == e) return true; while (gp[u].size()) { auto[v, i] = gp[u].back(); gp[u].pop_back(); if (vis[i]) continue; vis[i] = true; order.pb(i); if (dfs(v, e)) return true; order.pop_back(); } return false; } }; int n, m; VVPI gp; VI getpath(int s, int e, VI exclude) { GETPATH::vis = VI(m); for (int x : exclude) GETPATH::vis[x] = true; GETPATH::gp = gp; GETPATH::order = VI(); if (GETPATH::dfs(s, e)) return GETPATH::order; return {}; } VI reverse(VI a) { reverse(all(a)); return a; } VI vis; bool cyclecheck(int u, int p = -1) { vis[u] = true; for (auto[v, i] : gp[u]) if (v != p) { if (vis[v]) return true; if (cyclecheck(v, u)) return true; } return false; } variant<bool, VI> find_journey(int N, int M, VI U, VI V) { n = N; m = M; gp = VVPI(n); rep(i, m) { gp[U[i]].pb({V[i], i}); } if (N == 2) { if (gp[0].size() < 2 || gp[1].size() < 1) return false; VI ans; ans.pb(gp[0][0].ss); ans.pb(gp[1][0].ss); ans.pb(gp[0][1].ss); ans.pb(gp[0][0].ss); ans.pb(gp[1][0].ss); ans.pb(gp[0][1].ss); return ans; } vis = VI(n); if (cyclecheck(0)) return true; return VI{1, 4, 8, 8}; for (auto[v, i] : gp[0]) { VI ret = getpath(0, v, {i}); if (ret.size() == 0) continue; int het = -1; for (auto[u, i] : gp[v]) if (u == 0) het = i; if (het == -1) continue; VI ans; for (int x : ret) ans.pb(x); ans.pb(het); ans.pb(i); for (int x : reverse(ret)) ans.pb(x); ans.pb(het); ans.pb(i); return ans; } return false; }
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