이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#pragma GCC optimize("O1,O2,O3,Ofast,unroll-loops")
#include <bits/stdc++.h>
using namespace std;
#define fi first
#define se second
#define pb push_back
typedef long long ll;
typedef pair<int, int> ii;
typedef vector<int> vi;
const char nl = '\n';
void fastIO() {
ios::sync_with_stdio(false);
cin.tie(0);
}
int dirX[9] = {-1, -1, -1, 0, 0, 0, 1, 1, 1};
int dirY[9] = {-1, 0, 1, -1, 0, 1, -1, 0, 1};
int N, R;
int flat(int x, int y) {
if (x >= 0)
return x / y;
else
return -((-x + y - 1) / y);
}
bool intersect(ii c1, ii c2) {
ll dx = abs(c1.fi - c2.fi);
ll dy = abs(c1.se - c2.se);
if (4 * R * R >= dx * dx + dy * dy)
return true;
return false;
}
int main() {
fastIO();
int N;
cin>>N;
vector<ii> cr(N);
// {{x, y}, r}
for (int i = 0; i < N; i++) {
cin>>cr[i].fi>>cr[i].se;
cin>>R;
}
// cout<<"R: "<<R<<endl;
vector<ii> ft(N);
map<ii, set<int>> all;
for (int i = 0; i < N; i++) {
ft[i] = {flat(cr[i].fi, 2 * R), flat(cr[i].se, 2 * R)};
all[ft[i]].insert(i);
}
vector<bool> vis(N, false);
vi par(N, -1);
for (int i = 0; i < N; i++) {
if (vis[i])
continue;
int xc = ft[i].fi;
int yc = ft[i].se;
for (int j = 0; j < 9; j++) {
int xn = xc + dirX[j];
int yn = yc + dirY[j];
vi toerase;
for (int x : all[{xn, yn}]) {
if (!vis[x] && intersect(cr[i], cr[x])) {
vis[x] = true;
par[x] = i;
toerase.pb(x);
}
}
for (int x : toerase)
all[{xn, yn}].erase(x);
}
}
// cout<<"ANSWER: ";
for (int x : par)
cout<<x<<" ";
cout<<endl;
}
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