이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include "closing.h"
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
ll n, x, y, k, ans;
vector<vector<pair<int, ll> > > g(3e5);
vector<vector<ll> > d(2, vector<ll>(3e5, -1));
vector<ll> c(3e5, 0);
vector<vector<bool> > b(2, vector<bool>(3e5, false));
priority_queue<pair<ll, int> > pq;
void reset() {
for (int i = 0; i < n; i++) {
g[i].clear();
d[0][i] = d[1][i] = -1;
c[i] = 0;
b[0][i] = b[1][i] = false;
}
while (pq.size()) pq.pop();
ans = 0;
}
int max_score(int N, int X, int Y, ll K, vector<int> U, vector<int> V, vector<int> W) {
n = N;
x = X;
y = Y;
k = K;
reset();
for (int i = 0; i < n - 1; i++) {
g[U[i]].push_back({V[i], W[i]});
g[V[i]].push_back({U[i], W[i]});
}
d[0][x] = d[1][y] = 0;
pq.push({0, x});
pq.push({0, y + n});
while (pq.size()) {
int i = pq.top().second, j = 0;
pq.pop();
if (i >= n) {
i -= n;
j++;
}
if (b[j][i]) continue;
if (d[j][i] - c[i] > k) return ans;
k -= d[j][i] - c[i];
c[i] = d[j][i];
b[j][i] = true;
if (d[1 - j][i] > -1) pq.push({c[i] - d[1 - j][i], (1 - j ? i + n : i)});
ans++;
for (auto p: g[i]) {
ll l = p.first, w = p.second;
if (d[j][l] > -1) continue;
d[j][l] = d[j][i] + w;
int l2 = (j ? l + n : l);
pq.push({c[l] - d[j][l], l2});
}
}
return ans;
}
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