이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <stdio.h>
#include <algorithm>
using namespace std;
int n, k;
int m[100];
int str[100][10000];
int failure[10000];
bool ans;
void input ()
{
FILE* fp = stdin;
fscanf (fp, "%d%d", &n, &k);
for (int i=0; i<n; i++) {
fscanf (fp, "%d", &m[i]);
for (int j=0; j<m[i]; j++)
fscanf (fp, "%d", &str[i][j]);
}
}
void reverse (int m, int* arr)
{
for (int i=0; i<m/2; i++)
swap(arr[i], arr[m-i-1]);
}
// kmp algorithm
void get_failure_func (int* arr)
{
int j=-1;
failure[0] = -1;
for (int i=1; i<k; i++) {
while (j>=0 && arr[j+1] != arr[i])
j = failure[j];
if (arr[j+1] == arr[i]) j++;
failure[i] = j;
}
}
// kmp algorithm
bool find_string (int* p1, int m, int* p2)
{
int j=-1;
for (int i=0; i<m; i++) {
while (j>=0 && p2[j+1] != p1[i])
j = failure[j];
if (p2[j+1] == p1[i]) j++;
if (j == k-1)
return true;
}return false;
}
bool check_answer (int* p)
{
for (int i=1; i<n; i++) {
if (!find_string (str[i], m[i], p)) {
reverse (m[i], str[i]);
if (!find_string (str[i], m[i], p))
return false;
}
}
return true;
}
bool solve ()
{
if (m[0] < k) return false;
for (int i=0; i<=m[0]-k; i++) {
get_failure_func (str[0] + i);
if (check_answer (str[0] + i))
return true;
}
reverse (m[0], str[0]);
for (int i=0; i<=m[0]-k; i++) {
get_failure_func (str[0] + i);
if (check_answer (str[0] + i))
return true;
}
return false;
}
void output ()
{
FILE* fp = stdout;
if (ans) fprintf (fp, "YES\n");
else fprintf (fp, "NO\n");
}
int main()
{
input ();
ans = solve ();
output ();
return 0;
}
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