Submission #1069992

#TimeUsernameProblemLanguageResultExecution timeMemory
1069992NeroZeinA Light Inconvenience (CEOI23_light)C++17
0 / 100
321 ms592 KiB
#include "light.h"
#include <bits/stdc++.h>
using namespace std; 

const int LOG = 63;

int cnt;
long long sz;
vector<long long> indices;

void prepare(){
	cnt = 0;
	sz = 1; 
	indices.push_back(1); 
}

int msb(long long x) {
	for (int i = LOG - 1; i >= 0; --i) {
		if (x >> i & 1) {
			return i; 
		}
	}
	assert(false); 
}

pair<long long, vector<long long>> join(long long p){
	cnt++;
	sz += p;
	vector<long long> nindices = {sz}; 
	for (long long b = 1; b < sz - 1; b *= 2) {
		nindices.push_back(sz - b); 
	}
	nindices.push_back(1);
	reverse(nindices.begin(), nindices.end());
	indices = nindices; 
	return {p, indices};
}

pair<long long, vector<long long>> leave(long long p){// I just need to make sure after one leave I'm able to keep the rightmost lit
	cnt++;
	while (indices.back() > sz - p) {
		indices.pop_back(); 
	}
	sz -= p;
	if (indices.back() != sz) {
		indices.push_back(sz); 
	}
	return {p, indices};
}
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