Submission #1069533

#	Time	Username	Problem	Language	Result	Execution time	Memory
1069533		GrindMachine	Tricks of the Trade (CEOI23_trade)	C++17	25 / 100	1886 ms	2097152 KiB

trade

#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>

using namespace std;
using namespace __gnu_pbds;

template<typename T> using Tree = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
typedef long long int ll;
typedef long double ld;
typedef pair<int,int> pii;
typedef pair<ll,ll> pll;

#define fastio ios_base::sync_with_stdio(false); cin.tie(NULL)
#define pb push_back
#define endl '\n'
#define sz(a) (int)a.size()
#define setbits(x) __builtin_popcountll(x)
#define ff first
#define ss second
#define conts continue
#define ceil2(x,y) ((x+y-1)/(y))
#define all(a) a.begin(), a.end()
#define rall(a) a.rbegin(), a.rend()
#define yes cout << "Yes" << endl
#define no cout << "No" << endl

#define rep(i,n) for(int i = 0; i < n; ++i)
#define rep1(i,n) for(int i = 1; i <= n; ++i)
#define rev(i,s,e) for(int i = s; i >= e; --i)
#define trav(i,a) for(auto &i : a)

template<typename T>
void amin(T &a, T b) {
    a = min(a,b);
}

template<typename T>
void amax(T &a, T b) {
    a = max(a,b);
}

#ifdef LOCAL
#include "debug.h"
#else
#define debug(...) 42
#endif

/*



*/

const int MOD = 1e9 + 7;
const int N = 1e5 + 5;
const int inf1 = int(1e9) + 5;
const ll inf2 = ll(1e18) + 5;

void solve(int test_case)
{
    ll n,k; cin >> n >> k;
    vector<ll> a(n+5), b(n+5);
    rep1(i,n) cin >> a[i];
    rep1(i,n) cin >> b[i];    

    vector<vector<ll>> dp(n+5,vector<ll>(k+5,-1));

    auto go = [&](ll i, ll j, auto &&go) -> ll{
        if(j == 0) return 0;
        if(i > n) return -inf2;
        if(dp[i][j] != -1) return dp[i][j];
        ll ans = max(go(i+1,j,go)-a[i],go(i+1,j-1,go)-a[i]+b[i]);
        return dp[i][j] = ans;
    };

    ll ans = -inf2;
    rep1(i,n){
        amax(ans,go(i,k,go));
    }

    cout << ans << endl;
}

int main()
{
    fastio;

    int t = 1;
    // cin >> t;

    rep1(i, t) {
        solve(i);
    }

    return 0;
}

• Subtask 0: 0 / 0
• Subtask 1: 5 / 10
• Subtask 2: 5 / 10
• Subtask 3: 5 / 10
• Subtask 4: 10 / 25
• Subtask 5: 0 / 45