Submission #1068424

#	Time	Username	Problem	Language	Result	Execution time	Memory
1068424		Boas	Distributing Candies (IOI21_candies)	C++17	11 / 100	179 ms	15700 KiB

candies

#include "candies.h"

#include <bits/stdc++.h>
using namespace std;
#define int long long
typedef vector<int> vi;
typedef vector<signed> vi32;
typedef vector<bool> vb;
typedef vector<vi> vvi;
typedef set<int> si;
typedef pair<int, int> ii;
typedef vector<ii> vii;
typedef vector<vii> vvii;
#define pb push_back
#define loop(x, i) for (int i = 0; i < x; i++)
#define ALL(x) begin(x), end(x)
#define sz(x) (int)x.size()

vi lazy;
vi tree;

void applyLazy(int i, int l, int r, int v)
{
    tree[i] += v * (r - l + 1);
    lazy[i] += v;
}

int operation(int i, int l, int r, int ql, int qr, int v)
{
    if (qr < l || r < ql)
        return 0;
    int m = l + (r - l) / 2;

    // propagate
    {
        if (l != r)
        {
            applyLazy(2 * i, l, m, lazy[i]);
            applyLazy(2 * i + 1, m + 1, r, lazy[i]);
        }
        lazy[i] = 0;
    }

    if (ql <= l && r <= qr)
    {
        if (v != 0)
        {
            applyLazy(i, l, r, v);
        }
        return tree[i];
    }

    int res = operation(2 * i, l, m, ql, qr, v) +
              operation(2 * i + 1, m + 1, r, ql, qr, v);
    tree[i] = tree[2 * i] + tree[2 * i + 1];
    return res;
}

vi32 distribute_candies(vi32 c, vi32 l, vi32 r, vi32 v)
{
    int n = c.size();
    int q = sz(l);
    if (n <= 2000 && q <= 2000)
    {
        vi32 s(n);
        loop(q, i)
        {
            for (int p = l[i]; p <= r[i]; p++)
            {
                s[p] += v[i];
                s[p] = min(s[p], c[p]);
                s[p] = max(s[p], 0);
            }
        }
        return s;
    }
    int treeSz = 1;
    while (treeSz < n)
        treeSz *= 2;
    tree = lazy = vi(treeSz * 2);
    loop(q, i)
    {
        operation(1, 0, treeSz - 1, l[i], r[i], v[i]);
    }
    vi32 s(n);
    loop(n, i)
    {
        s[i] = (signed)min(operation(1, 0, treeSz - 1, i, i, 0), (int)c[i]);
    }
    return s;
}

• Subtask 1: 3 / 3
• Subtask 2: 8 / 8
• Subtask 3: 0 / 27
• Subtask 4: 0 / 29
• Subtask 5: 0 / 33