제출 #1067024

#제출 시각아이디문제언어결과실행 시간메모리
1067024GrindMachineChorus (JOI23_chorus)C++17
16 / 100
476 ms1048576 KiB
#include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> using namespace std; using namespace __gnu_pbds; template<typename T> using Tree = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>; typedef long long int ll; typedef long double ld; typedef pair<int,int> pii; typedef pair<ll,ll> pll; #define fastio ios_base::sync_with_stdio(false); cin.tie(NULL) #define pb push_back #define endl '\n' #define sz(a) (int)a.size() #define setbits(x) __builtin_popcountll(x) #define ff first #define ss second #define conts continue #define ceil2(x,y) ((x+y-1)/(y)) #define all(a) a.begin(), a.end() #define rall(a) a.rbegin(), a.rend() #define yes cout << "Yes" << endl #define no cout << "No" << endl #define rep(i,n) for(int i = 0; i < n; ++i) #define rep1(i,n) for(int i = 1; i <= n; ++i) #define rev(i,s,e) for(int i = s; i >= e; --i) #define trav(i,a) for(auto &i : a) template<typename T> void amin(T &a, T b) { a = min(a,b); } template<typename T> void amax(T &a, T b) { a = max(a,b); } #ifdef LOCAL #include "debug.h" #else #define debug(...) 42 #endif /* read the edi some time ago, remember some ideas from there */ const int MOD = 1e9 + 7; const int N = 1e5 + 5; const int inf1 = int(1e9) + 5; const ll inf2 = ll(1e18) + 5; void solve(int test_case) { int n,k; cin >> n >> k; string s; cin >> s; s = "$" + s; n <<= 1; vector<int> p(n+5); rep1(i,n) p[i] = p[i-1]+(s[i]=='A'); int dp[n+5][n+5][n+5][n+5][n+5]; memset(dp,0x3f,sizeof dp); dp[0][0][0][0][0] = 0; rep(i,n){ int x = p[i+1]; rep(ignore_cnt,n+1){ rep(ones,n+1){ rep(active_ones,n+1){ rep(c,n+1){ int curr = dp[i][ignore_cnt][ones][active_ones][c]; // A amin(dp[i+1][ignore_cnt][ones+1][active_ones+1][c+(active_ones==0)],curr+abs(ones+1-x)); // B if(ignore_cnt){ amin(dp[i+1][ignore_cnt-1][ones][active_ones][c],curr+abs(ones-x)); } else{ if(active_ones){ amin(dp[i+1][active_ones-1][ones][0][c],curr+abs(ones-x)); } } } } } } } int ans = inf1; rep(c,k+1){ amin(ans,dp[n][0][n/2][0][c]); } cout << ans << endl; } int main() { fastio; int t = 1; // cin >> t; rep1(i, t) { solve(i); } return 0; }
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