Submission #1065893

#TimeUsernameProblemLanguageResultExecution timeMemory
1065893GrindMachineSoccer Stadium (IOI23_soccer)C++17
100 / 100
3202 ms1070192 KiB
#include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> using namespace std; using namespace __gnu_pbds; template<typename T> using Tree = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>; typedef long long int ll; typedef long double ld; typedef pair<int,int> pii; typedef pair<ll,ll> pll; #define fastio ios_base::sync_with_stdio(false); cin.tie(NULL) #define pb push_back #define endl '\n' #define sz(a) (int)a.size() #define setbits(x) __builtin_popcountll(x) #define ff first #define ss second #define conts continue #define ceil2(x,y) ((x+y-1)/(y)) #define all(a) a.begin(), a.end() #define rall(a) a.rbegin(), a.rend() #define yes cout << "Yes" << endl #define no cout << "No" << endl #define rep(i,n) for(int i = 0; i < n; ++i) #define rep1(i,n) for(int i = 1; i <= n; ++i) #define rev(i,s,e) for(int i = s; i >= e; --i) #define trav(i,a) for(auto &i : a) template<typename T> void amin(T &a, T b) { a = min(a,b); } template<typename T> void amax(T &a, T b) { a = max(a,b); } #ifdef LOCAL #include "debug.h" #else #define debug(x) 42 #endif /* refs: https://blog.brucemerry.org.za/2023/11/ioi-2023-day-1.html */ const int MOD = 1e9 + 7; const int N = 2e3 + 5; const int inf1 = int(1e9) + 5; const ll inf2 = ll(1e18) + 5; #include "soccer.h" template<typename T> struct sparse_table { /*============================*/ T merge(T a, T b) { return max(a,b); } /*============================*/ vector<vector<T>> table; vector<int> bin_log; int LOG = 0; sparse_table() { } sparse_table(vector<T> &a, int n) { while ((1 << LOG) <= n) LOG++; table = vector<vector<T>>(n, vector<T>(LOG)); bin_log = vector<int>(n + 1); rep(i, n) table[i][0] = a[i]; rep1(j, LOG - 1) { rep(i, n) { int jump = 1 << (j - 1); if (i + jump >= n) { break; } table[i][j] = merge(table[i][j - 1], table[i + jump][j - 1]); } } bin_log[1] = 0; for (int i = 2; i <= n; ++i) { bin_log[i] = bin_log[i / 2] + 1; } } T query(int l, int r) { int len = r - l + 1; int k = bin_log[len]; T val1 = table[l][k]; T val2 = table[r - (1 << k) + 1][k]; return merge(val1, val2); } }; int mnl[N][N], mxr[N][N], mnu[N][N]; sparse_table<int> st1[N], st2[N]; int extendl(int i, int j, int c){ // int mx = -inf1; // for(int r = i; r <= j; ++r){ // amax(mx,mnl[r][c]); // } // return mx; return st1[c].query(i,j); } int extendr(int i, int j, int c){ // int mn = inf1; // for(int r = i; r <= j; ++r){ // amin(mn,mxr[r][c]); // } // return mn; return -st2[c].query(i,j); } const vector<ll> mul = {34828472,4838748374,894587283}; typedef unsigned long long ull; struct hsh{ const ull RANDOM = mt19937_64(chrono::steady_clock::now().time_since_epoch().count())(); ull operator()(const array<int,3> &a) const { ull val = a[0]*mul[0]+a[1]*mul[1]+a[2]*mul[2]; val ^= RANDOM; return val; } }; int n; gp_hash_table<array<int,3>,int,hsh> mp; int go(int i, int j, int l){ if(i > j) return 0; l = extendl(i,j,l); int r = extendr(i,j,l); array<int,3> ar = {i,j,l}; if(mp.find(ar) != mp.end()) return mp[ar]; int len = r-l+1; // shrink j int ans = len+go(i,j-1,l); // shrink i till l expansion possible if(l-1){ int p = mnu[j][l-1]; amax(ans,len*(p-i)+go(p,j,l)); } // shrink i till r expansion possible if(r+1 <= n){ int p = mnu[j][r+1]; amax(ans,len*(p-i)+go(p,j,l)); } return mp[ar] = ans; } int biggest_stadium(int n_, std::vector<std::vector<int>> A) { n = n_; int a[n+5][n+5]; memset(a,0,sizeof a); rep1(i,n) rep1(j,n) a[i][j] = A[i-1][j-1]; rep1(i,n) mnl[i][0] = 1; rep1(i,n){ rep1(j,n){ if(!a[i][j]){ mnl[i][j] = mnl[i][j-1]; } else{ mnl[i][j] = j+1; } } } rep1(i,n) mxr[i][n+1] = n; rev(j,n,1){ rep1(i,n){ if(!a[i][j]){ mxr[i][j] = mxr[i][j+1]; } else{ mxr[i][j] = j-1; } } } rep1(j,n){ vector<int> b(n+5); rep1(i,n) b[i] = mnl[i][j]; st1[j] = sparse_table<int>(b,n+1); } rep1(j,n){ vector<int> b(n+5); rep1(i,n) b[i] = -mxr[i][j]; st2[j] = sparse_table<int>(b,n+1); } rep1(j,n) mnu[0][j] = 1; rep1(i,n){ rep1(j,n){ if(!a[i][j]){ mnu[i][j] = mnu[i-1][j]; } else{ mnu[i][j] = i+1; } } } int ans = 0; vector<int> lx(n+5); rep1(i,n){ rep1(j,n) lx[j] = 1; stack<int> stk; rev(j,n,1){ while(!stk.empty() and mnu[i][j] > mnu[i][stk.top()]){ int k = stk.top(); lx[k] = j+1; stk.pop(); } stk.push(j); } rep1(j,n){ amax(ans,go(mnu[i][j],i,lx[j])); } } return ans; }
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