제출 #1064296

#제출 시각아이디문제언어결과실행 시간메모리
1064296ewirlanRectangles (IOI19_rect)C++17
0 / 100
97 ms165568 KiB
// #ifndef __SIZEOF_INT128__ #define __SIZEOF_INT128__ #endif #pragma GCC optimize("Ofast") #include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> using namespace std; using namespace chrono; using namespace __gnu_pbds; template <typename T> using oset = tree<T, null_type, less_equal<T>, rb_tree_tag, tree_order_statistics_node_update>; #define rep(i, p, k) for(int i(p); i < (k); ++i) #define per(i, p, k) for(int i(p); i > (k); --i) #define sz(x) (int)(x).size() #define sc static_cast typedef long long ll; typedef long double ld; typedef unsigned int uint; typedef unsigned long long ull; typedef __int128_t lll; //#define int ll template <typename T = int> using par = std::pair <T, T>; #define fi first #define se second #define test int _number_of_tests(in()); while(_number_of_tests--) #define all(x) (x).begin(), (x).end() #define rall(x) (x).rbegin(), (x).rend() #define pb emplace_back struct Timer { string name{""}; time_point<high_resolution_clock> end, start{high_resolution_clock::now()}; duration<float, std::milli> dur; Timer() = default; Timer(string nm): name(nm) {} ~Timer() { end = high_resolution_clock::now(); dur= end - start; cout << "@" << name << "> " << dur.count() << " ms" << '\n'; } }; template <typename T = int> inline T in() { static T x; std::cin >> x; return x; } std::string yn(bool b) { if(b) return "YES\n"; else return "NO\n"; } template <typename F, typename S> std::ostream& operator<<(std::ostream& out, const std::pair <F, S>& par); template <typename T> std::ostream& operator<< (std::ostream& out, const std::vector <T>& wek) { for(const auto& i : wek)out << i << ' '; return out; } template <typename F, typename S> std::ostream& operator<<(std::ostream& out, const std::pair <F, S>& par) { out << '{'<<par.first<<", "<<par.second<<"}"; return out; } #define show(x) cerr << #x << " = " << x << '\n'; constexpr int maxa = 7e6 +3, maxn = 2503, maxs = maxn*maxn; vector <pair <int, int>> v[maxa]; bool on[maxn][maxn]; int pti(pair <int, int> p){return 1+p.first * maxn + p.second;} array <int, maxs> rp, xl, xr, yl, yr, si; int find(int w){ if(!rp[w])return w; return rp[w] = find(rp[w]); } void uni(pair <int, int> pa, pair <int, int> pb){ int a(find(pti(pa))), b(find(pti(pb))); if(a == b)return; rp[a] = b; si[b] += si[a]; xl[b] = min(xl[b], xl[a]); xr[b] = max(xr[b], xr[a]); yl[b] = min(yl[b], yl[a]); yr[b] = max(yr[b], yr[a]); } ll count_rectangles(vector <vector <int>> a) { int n(sz(a)), m(sz(a[0])); rep(i, 0, n)rep(j, 0, m){ int g(pti({i, j})); si[g] = 1; xl[g] = xr[g] = i; yl[g] = yr[g] = j; } rep(i, 0, n)rep(j, 0, m)v[a[i][j]].pb(i, j); ll o(0); rep(i, 0, maxa)if(sz(v[i])){ set <int> tupd; for(auto [x, y]: v[i]){ on[x][y] = 1; if(x > 0 && on[x-1][y])uni({x, y}, {x-1, y}); if(x < n-1 && on[x+1][y])uni({x, y}, {x+1, y}); if(y > 0 && on[x][y-1])uni({x, y}, {x, y-1}); if(y < m-1 && on[x][y+1])uni({x, y}, {x, y+1}); tupd.insert(find(pti({x, y}))); } for(auto r: tupd)if(find(r) == r && si[r] == (xr[r] - xr[r]+1)*(yr[r] - yl[r]+1))++o; // cerr << i << "---------------"; // for(auto i: v[i])cerr << pti(i) << ' '; // cerr << '\n'; // rep(i, 0, n){ // rep(j, 0, m)cerr << find(pti({i, j})) << ' '; // cerr << '\n'; // } } return o; }
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