이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#include "books.h"
using namespace std;
typedef long long ll;
typedef pair<int, int> pii;
#define pb push_back
#define F first
#define S second
#define sz(x) (int)x.size()
const int N = 5e5;
int n, k, mx;
void solve(int N, int K, long long A, int S) {
n = N;
k = K;
mx = A;
int lo = 0, hi = n + 1;
while(lo + 1 < hi){
int m = (lo + hi) / 2;
int x = skim(m);
if(x > A)
hi = m;
else
lo = m;
}
if(hi < k)
impossible();
vector<pair<ll, ll>> ha = {};
if(2 * k < hi){
for(int i = 1; i <= k; i++){
ha.pb({i, skim(i)});
}
for(int i = hi - k; i < hi; i++){
ha.pb({i, skim(i)});
}
}else{
for(int i = 1; i < hi; i++)
ha.pb({i, skim(i)});
}
ll sm = 0;
if(hi <= n){
sm += skim(hi);
for(int i = 1; i < k; i++){
sm += ha[i - 1].S;
}
if(sm >= A && sm <= 2 * A){
vector<int> ret = {};
for(int i = 1; i < k; i++)
ret.pb(i);
ret.pb(hi);
answer(ret);
return;
}
}
sm = 0;
int cur = k - 2;
while(sm < A){
cur++;
if(cur == sz(ha))
break;
sm = 0;
for(int i = cur - k + 1; i <= cur; i++)
sm += ha[i].S;
}
if(cur == sz(ha))
impossible();
vector<int> ret = {};
for(int i = cur - k + 1; i <= cur; i++)
ret.pb(i + 1);
answer(ret);
}
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