답안 #106386

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
106386 2019-04-18T08:26:50 Z polyfish 코알라 (APIO17_koala) C++14
61 / 100
65 ms 532 KB
#include "koala.h"
#include <bits/stdc++.h>
using namespace std;

#define debug(x) cerr << #x << " = " << x << '\n';
#define BP() cerr << "OK!\n";
#define PR(A, n) {cerr << #A << " = "; for (int _=1; _<=n; ++_) cerr << A[_] << ' '; cerr << '\n';}
#define PR0(A, n) {cerr << #A << " = "; for (int _=0; _<n; ++_) cerr << A[_] << ' '; cerr << '\n';}
#define FILE_NAME "data"

const int MAX_N = 202;

int b[MAX_N], r[MAX_N], a[MAX_N];
pair<int, int> f[MAX_N][MAX_N];

int minValue(int N, int W) {
    // TODO: Implement Subtask 1 solution here.

    b[0] = 1;
    playRound(b, r);

    for (int i=0; i<N; ++i) {
        if (r[i]==0)
            return i;
    }

    return 0;
}

void trace(int n, int w, int& cnt) {
    if (w==0)
        return;

    if (f[n][w]==f[n-1][w])
        return trace(n-1, w, cnt);

    cnt += (a[n]==*max_element(a+1, a+100+1));
    trace(n-1, w-a[n]-1, cnt);
}

void test() {
    int n = 100, w = 100;
    // TODO: Implement Subtask 2 solution here.

    for (int i=1; i<=91; ++i)
        a[i] = 0;
    for (int i=92; i<=100; ++i)
        a[i] = 11;

    for (int i=1; i<=n; ++i) {
        for (int j=0; j<=w; ++j) {
            f[i][j] = f[i-1][j];
            if (j>a[i])
                f[i][j] = max(f[i][j], {f[i-1][j-a[i]-1].first + i, f[i-1][j-a[i]-1].second+1});
        }
    }
    debug(f[n][w].first);
    debug(f[n][w].second);
    int cnt = 0;
    trace(n, w, cnt);
    debug(cnt);
}

int maxValue(int n, int w) {
    // TODO: Implement Subtask 2 solution here.

//    test();
    vector<int> b0, b1, b2, b3;

    ///Round 1
    for (int i=0; i<n; ++i)
        b[i] = 1;
    playRound(b, r);
    for (int i=0; i<n; ++i) {
        if (r[i])
            b1.push_back(i);
        else
            b0.push_back(i);
    }

    ///Round 2
    for (auto x : b0)
        b[x] = 0;
    for (auto x : b1)
        b[x] = 2;
    memset(r, 0, sizeof(r));
    playRound(b, r);
    for (auto x : b1) {
        if (r[x]>=3)
            b2.push_back(x);
    }
    for (auto x : b2)
        b1.erase(find(b1.begin(), b1.end(), x));

    ///Round 3
    for (auto x : b0)
        b[x] = 0;
    for (auto x : b1)
        b[x] = 1;
    for (auto x : b2)
        b[x] = 3;
    memset(r, 0, sizeof(r));
    playRound(b, r);
    for (auto x : b2) {
        if (r[x]>=4)
            b3.push_back(x);
    }
    for (auto x : b3)
        b2.erase(find(b2.begin(), b2.end(), x));


    ///Round 4
    memset(b, 0, sizeof(b));
    for (auto x : b3)
        b[x] = 16;
    memset(r, 0, sizeof(r));
    playRound(b, r);
    for (auto x : b3) {
        if (r[x]>=17)
            return x;
    }

    return 0;
}

int greaterValue(int n, int w) {
    // TODO: Implement Subtask 3 solution here.

    vector<int> cur;
    for (int i=0; i<n; ++i)
        cur.push_back(i);

    #define Find(v, x) find(v.begin(), v.end(), x)!=v.end()

//    for (int i=1; i<=13; ++i) {
//        memset(r, 0, sizeof(r));
//        b[0] = b[1] = i;
//        playRound(b, r);
//        if (r[0]>i && r[1]<=i)
//            return 0;
//        if (r[0]<=i && r[1]>i)
//            return 1;
//    }

    int l = 1, h = 14;
    while (true) {
        int mid = (l + h) / 2;
        memset(r, 0, sizeof(r));
        b[0] = b[1] = mid;
        playRound(b, r);
        if (r[0]==r[1] && r[1]==0)
            h = mid - 1;
        else if (r[0]==r[1] && r[1]>0)
            l = mid + 1;
        else if (r[0]<r[1])
            return 1;
        else
            return 0;
    }

    #undef Find

    return 0;
}

void allValues(int n, int w, int *P) {
    if (w == 2*n) {
        // TODO: Implement Subtask 4 solution here.
        // You may leave this block unmodified if you are not attempting this
        // subtask.
    } else {
        // TODO: Implement Subtask 5 solution here.

        vector<int> p(n);
        for (int i=0; i<n; ++i)
            p[i] = i;

        sort(p.begin(), p.end(), [](int x, int y) {
            int l = 1, h = 14;
            while (true) {
                int mid = (l + h) / 2;
                memset(r, 0, sizeof(r));
                memset(b, 0, sizeof(b));
                b[x] = b[y] = mid;
                playRound(b, r);
                if (r[x]==r[y] && r[y]==0)
                    h = mid - 1;
                else if (r[x]==r[y] && r[y]>0)
                    l = mid + 1;
                else if (r[x]<r[y])
                    return true;
                else
                    return false;
            }
        });

        for (int i=0; i<n; ++i)
            P[p[i]] = i+1;
    }
}
# 결과 실행 시간 메모리 Grader output
1 Correct 6 ms 384 KB Output is correct
2 Correct 6 ms 384 KB Output is correct
3 Correct 5 ms 384 KB Output is correct
4 Correct 6 ms 384 KB Output is correct
# 결과 실행 시간 메모리 Grader output
1 Correct 15 ms 384 KB Output is correct
2 Correct 15 ms 384 KB Output is correct
3 Correct 15 ms 384 KB Output is correct
4 Correct 15 ms 384 KB Output is correct
# 결과 실행 시간 메모리 Grader output
1 Correct 44 ms 424 KB Output is correct
2 Correct 50 ms 420 KB Output is correct
3 Correct 43 ms 384 KB Output is correct
4 Correct 49 ms 384 KB Output is correct
5 Correct 65 ms 512 KB Output is correct
6 Correct 53 ms 384 KB Output is correct
7 Correct 43 ms 384 KB Output is correct
8 Correct 50 ms 384 KB Output is correct
9 Correct 55 ms 512 KB Output is correct
10 Correct 50 ms 384 KB Output is correct
# 결과 실행 시간 메모리 Grader output
1 Incorrect 2 ms 428 KB Output isn't correct
2 Halted 0 ms 0 KB -
# 결과 실행 시간 메모리 Grader output
1 Partially correct 26 ms 384 KB Output is partially correct
2 Partially correct 38 ms 504 KB Output is partially correct
3 Partially correct 34 ms 384 KB Output is partially correct
4 Partially correct 27 ms 384 KB Output is partially correct
5 Partially correct 35 ms 432 KB Output is partially correct
6 Partially correct 31 ms 384 KB Output is partially correct
7 Partially correct 33 ms 476 KB Output is partially correct
8 Partially correct 36 ms 384 KB Output is partially correct
9 Partially correct 34 ms 384 KB Output is partially correct
10 Partially correct 30 ms 384 KB Output is partially correct
11 Partially correct 32 ms 384 KB Output is partially correct
12 Partially correct 21 ms 384 KB Output is partially correct
13 Partially correct 31 ms 384 KB Output is partially correct
14 Partially correct 57 ms 384 KB Output is partially correct
15 Partially correct 28 ms 384 KB Output is partially correct
16 Partially correct 35 ms 396 KB Output is partially correct
17 Partially correct 35 ms 384 KB Output is partially correct
18 Partially correct 33 ms 384 KB Output is partially correct
19 Partially correct 27 ms 384 KB Output is partially correct
20 Partially correct 31 ms 384 KB Output is partially correct
21 Partially correct 33 ms 384 KB Output is partially correct
22 Partially correct 38 ms 384 KB Output is partially correct
23 Partially correct 26 ms 384 KB Output is partially correct
24 Partially correct 32 ms 384 KB Output is partially correct
25 Partially correct 32 ms 384 KB Output is partially correct
26 Partially correct 34 ms 504 KB Output is partially correct
27 Partially correct 34 ms 384 KB Output is partially correct
28 Partially correct 34 ms 384 KB Output is partially correct
29 Partially correct 33 ms 384 KB Output is partially correct
30 Partially correct 33 ms 384 KB Output is partially correct
31 Partially correct 30 ms 384 KB Output is partially correct
32 Partially correct 32 ms 384 KB Output is partially correct
33 Partially correct 52 ms 384 KB Output is partially correct
34 Partially correct 29 ms 384 KB Output is partially correct
35 Partially correct 27 ms 384 KB Output is partially correct
36 Partially correct 28 ms 384 KB Output is partially correct
37 Partially correct 40 ms 384 KB Output is partially correct
38 Partially correct 44 ms 532 KB Output is partially correct
39 Partially correct 42 ms 384 KB Output is partially correct
40 Partially correct 28 ms 504 KB Output is partially correct