제출 #106286

#제출 시각아이디문제언어결과실행 시간메모리
106286hugo_pmExamination (JOI19_examination)C++17
100 / 100
2001 ms798092 KiB
#include <bits/stdc++.h> using namespace std; #define int long long #define form2(i, a, b) for (int i = (a); i < (b); ++i) #define ford2(i, a, b) for (int i = (a-1); i >= b; --i) #define form(i, n) form2(i, 0, n) #define ford(i, n) ford2(i, n, 0) #define chmax(x, v) x = max(x, (v)) #define chmin(x, v) x = min(x, (v)) #define fi first #define se second const long long BIG = 1000000000000000000LL; typedef long long ll; typedef long double ld; typedef pair<int, int> pii; void cpr(string s, vector<int> v) { int i = 0; for (char c : s) { if (c == '$') cout << v[i++]; else cout << c; } cout << '\n'; } void cpr(string s) { cpr(s, {}); } void solve(); signed main() { ios::sync_with_stdio(false); cin.tie(0); solve(); return 0; } const int borne2 = (1LL << 40LL); struct Node { int val; pii itv; Node *lc=nullptr, *rc=nullptr; Node* left(); Node* right(); void init() { val=0; itv = {0, borne2-1}; lc=nullptr; rc=nullptr; } int requete(int a, int b) { if (itv.fi > b || itv.se < a) return 0; if (a <= itv.fi && itv.se <= b) return val; return left()->requete(a,b) + right()->requete(a,b); } void incr(int x) { if (itv.fi > x || itv.se < x) return; if (itv.fi == x && itv.se == x) { ++val; return; } left()->incr(x); right()->incr(x); val = left()->val + right()->val; } }; const int MAX_BUF = 1000*1000*1000 / 50; Node buf[MAX_BUF]; int lsBuf = 0; Node* Node::left() { if (lc == nullptr) { lc = &buf[lsBuf++]; lc->val = 0; lc->itv = {itv.fi, (itv.fi+itv.se)/2LL}; } return lc; } Node* Node::right() { if (rc == nullptr) { rc = &buf[lsBuf++]; rc->val = 0; rc->itv = {(itv.fi+itv.se)/2LL + 1LL, itv.se}; } return rc; } struct Requete { int maths=0, info=0, rqAdd=0, tot=0, rep=0, ind=0; }; bool cmpAdd(Requete a, Requete b) { return tie(a.rqAdd, a.ind) < tie(b.rqAdd, b.ind); } bool cmpMaths(Requete a, Requete b) { return tie(a.maths, a.ind) < tie(b.maths, b.ind); } bool cmpInd(Requete a, Requete b) { return a.ind < b.ind; } const int borne = 4 * ((int)(1e5) + 5); pii etud[borne]; Requete req[borne]; int nbEtud, nbReq; Node* sc; Node* oth; void bourrin() { form(i, nbEtud) cin >> etud[i].fi >> etud[i].se; form(iReq, nbReq) { int crMaths, crInfo, crTot; cin >> crMaths >> crInfo >> crTot; int rep = 0; form(indEtud, nbEtud) { auto &ed = etud[indEtud]; if (ed.fi >= crMaths && ed.se >= crInfo && ed.fi + ed.se >= crTot) { ++rep; } } cout << rep << "\n"; } } void solve() { cin >> nbEtud >> nbReq; if (nbEtud <= 3000 && nbReq <= 3000) { bourrin(); return; } form(i, nbEtud) cin >> etud[i].fi >> etud[i].se; sort(etud, etud+nbEtud); form(i, nbReq) { cin >> req[i].maths >> req[i].info >> req[i].tot; req[i].rqAdd = req[i].tot - req[i].info; req[i].ind = i; } sort(req, req+nbReq, cmpAdd); vector<int> tmp(borne, 0); sc = &buf[lsBuf++]; oth = &buf[lsBuf++]; sc->init(); oth->init(); int iAdd = nbEtud-1; ford(iReq, nbReq) { auto &cur = req[iReq]; while (iAdd >= 0 && etud[iAdd].fi >= cur.rqAdd) { int ol = etud[iAdd].se; sc->incr(ol); int ol2 = etud[iAdd].se + etud[iAdd].fi; oth->incr(ol2); --iAdd; } cur.rep = sc->requete(cur.info, borne2-1); int lim = cur.tot; chmin(lim, borne2-1); chmax(lim, 0LL); cur.rep -= oth->requete(lim, borne2-1); } sc = &buf[lsBuf++]; oth = &buf[lsBuf++]; sc->init(); oth->init(); sort(req, req+nbReq, cmpMaths); iAdd=nbEtud-1; ford(iReq, nbReq) { auto &cur = req[iReq]; while (iAdd >= 0 && etud[iAdd].fi >= cur.maths) { int ol = etud[iAdd].se; sc->incr(ol); int ol2 = etud[iAdd].se + etud[iAdd].fi; oth->incr(ol2); --iAdd; } if (cur.maths + cur.info >= cur.tot) { cur.rep = sc->requete(cur.info, borne2-1); continue; } int lim = cur.tot; chmin(lim, borne2-1); chmax(lim, 0LL); cur.rep += oth->requete(lim, borne2-1); } sort(req, req+nbReq, cmpInd); form(iReq, nbReq) { cout << req[iReq].rep << "\n"; } }
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