# | Time | Username | Problem | Language | Result | Execution time | Memory |
---|---|---|---|---|---|---|---|
1062667 | Arapak | Digital Circuit (IOI22_circuit) | C++17 | 0 ms | 0 KiB |
This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include "circuit.h"
#include "bits/stdc++.h"
using namespace std;
#define rep(i,a,b) for(int i=(a);i<(b);++i)
#define sz(x) (int)x.size()
#define all(x) begin(x), end(x)
typedef vector<int> vi;
typedef pair<int,int> pii;
typedef long long ll;
#ifdef DEBUG
auto& operator<<(auto& os, pair<auto, auto> &p) {
return os<<"("<<p.first<<", "<<p.second<<")";
}
auto& operator<<(auto& os, const auto &v) {
os<<"{";
for(auto it=begin(v);it!=end(v);++it) {
if(it != begin(v)) os<<", ";
os<<(*it);
}
return os<<"}";
}
void dbg_out(auto... x) {
((cerr<<' '<<x), ...) << endl;
}
#define dbg(x...) cerr<<"("<<#x<<"):", dbg_out(x);
#else
#define dbg(...)
#endif
const ll mod = 1000002022;
int n, m;
vi p, a;
vector<vi> g;
bool tree_subtask;
bool is_tree_subtask() {
int b = (int)bit_ceil(uint(m));
if(b != m || m != n+1) return false;
rep(i,1,n+m)
if(p[i] != (i-1) / 2) return false;
return true;
}
void init(int N, int M, vi P, vi A) {
n = N; m = M; p = P; a = A;
tree_subtask = is_tree_subtask();
g.resize(n);
rep(i,1,n+m)
g[p[i]].push_back(i);
}
vector<ll> multiply(const vector<ll> &a, const vector<ll> &b) {
vector<ll> res(sz(a) + sz(b) - 1);
rep(i,0,sz(a)) rep(j,0,sz(b))
res[i+j] = (res[i+j] + a[i] * b[j]) % mod;
dbg(a, b, res);
return res;
}
int count_ways(int L, int R) {
dbg(L, R);
rep(i,L,R+1)
a[i-n] = !a[i-n];
dbg(a);
vector<vector<ll>> dp(n+m);
rep(i,0,m) dp[n+i] = a[i] ? vector<ll>({0, 1}) : vector<ll>({1, 0});
for(int i=n-1;i>=0;i--) {
dbg(i);
vector<vector<ll>> v = {{1, 0}};
for(auto e : g[i]) {
dbg(e);
vector<ll> vec = dp[e];
while(!v.empty() && sz(v.back()) == sz(vec)) {
vec = multiply(vec, v.back());
v.pop_back();
}
v.push_back(vec);
dbg(v);
}
while(sz(v) > 1) {
auto a = v.back(); v.pop_back();
auto b = v.back(); v.pop_back();
v.push_back(multiply(a, b));
}
const vector<ll> &val = v[0];
dbg(val);
dp[i] = {0, 0};
ll all = 0;
rep(j,0,sz(g[i]) + 1)
all = (all + val[j]) % mod;
ll sum = val[0];
rep(j,1,sz(g[i]) + 1) {
dp[i][0] = (dp[i][0] + sum) % mod;
dp[i][1] = (dp[i][1] + all + mod - sum) % mod;
sum = (sum + val[j]) % mod;
}
}
return dp[0][1];
}