Submission #1061236

#TimeUsernameProblemLanguageResultExecution timeMemory
1061236GrindMachineLamps (JOI19_lamps)C++17
100 / 100
221 ms49612 KiB
#include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> using namespace std; using namespace __gnu_pbds; template<typename T> using Tree = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>; typedef long long int ll; typedef long double ld; typedef pair<int,int> pii; typedef pair<ll,ll> pll; #define fastio ios_base::sync_with_stdio(false); cin.tie(NULL) #define pb push_back #define endl '\n' #define sz(a) (int)a.size() #define setbits(x) __builtin_popcountll(x) #define ff first #define ss second #define conts continue #define ceil2(x,y) ((x+y-1)/(y)) #define all(a) a.begin(), a.end() #define rall(a) a.rbegin(), a.rend() #define yes cout << "Yes" << endl #define no cout << "No" << endl #define rep(i,n) for(int i = 0; i < n; ++i) #define rep1(i,n) for(int i = 1; i <= n; ++i) #define rev(i,s,e) for(int i = s; i >= e; --i) #define trav(i,a) for(auto &i : a) template<typename T> void amin(T &a, T b) { a = min(a,b); } template<typename T> void amax(T &a, T b) { a = max(a,b); } #ifdef LOCAL #include "debug.h" #else #define debug(...) 42 #endif /* read some solutions a long time ago, remember some key ideas from there */ const int MOD = 1e9 + 7; const int N = 1e5 + 5; const int inf1 = int(1e9) + 5; const ll inf2 = ll(1e18) + 5; void solve(int test_case) { int n; cin >> n; vector<int> a(n+5), b(n+5); rep1(i,n){ char ch; cin >> ch; a[i] = ch-'0'; } rep1(i,n){ char ch; cin >> ch; b[i] = ch-'0'; } int m = 10; int c[m][m]; auto get = [&](int x){ vector<int> v = {-1}; if(x == 1) v.pb(0); if(x == 2) v.pb(1); if(x == 3) v.pb(2); if(x == 4) v.pb(0), v.pb(1); if(x == 5) v.pb(0), v.pb(2); if(x == 6) v.pb(1), v.pb(0); if(x == 7) v.pb(1), v.pb(2); if(x == 8) v.pb(2), v.pb(0); if(x == 9) v.pb(2), v.pb(1); return v; }; rep(x,m){ rep(y,m){ auto v1 = get(x), v2 = get(y); int dp[sz(v1)][sz(v2)]; memset(dp,0,sizeof dp); rep1(i,sz(v1)-1){ rep1(j,sz(v2)-1){ dp[i][j] = max(dp[i][j-1],dp[i-1][j]); if(v1[i] == v2[j]){ amax(dp[i][j],dp[i-1][j-1]+1); } } } int lcs = dp[sz(v1)-1][sz(v2)-1]; c[x][y] = sz(v2)-lcs-1; } } int fv[m][2]; rep(j,m){ rep(k,2){ int x = k; if(j == 1) x = 0; if(j == 2) x = 1; if(j == 3) x ^= 1; if(j == 4) x = 0, x = 1; if(j == 5) x = 0, x ^= 1; if(j == 6) x = 1, x = 0; if(j == 7) x = 1, x ^= 1; if(j == 8) x ^= 1, x = 0; if(j == 9) x ^= 1, x = 1; fv[j][k] = x; } } int dp[n+5][m]; memset(dp,0x3f,sizeof dp); dp[1][0] = 0; rep1(i,n){ rep(j,m){ rep(k,m){ int v = fv[k][a[i]]; if(v == b[i]){ amin(dp[i+1][k],dp[i][j]+c[j][k]); } } } } int ans = inf1; rep(j,m) amin(ans,dp[n+1][j]); cout << ans << endl; } int main() { fastio; int t = 1; // cin >> t; rep1(i, t) { solve(i); } return 0; }
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