제출 #1060545

#제출 시각아이디문제언어결과실행 시간메모리
1060545n1k봉쇄 시간 (IOI23_closing)C++17
8 / 100
89 ms36652 KiB
#include "closing.h" #include <bits/stdc++.h> using namespace std; using ll = long long; int max_score(int N, int X, int Y, long long K, vector<int> U, vector<int> V, vector<int> W){ vector<vector<array<int, 2>>> g(N); vector c(2, vector<ll>(N)); vector<int> par(N); for(int i=0; i<N-1; i++){ g[U[i]].push_back({V[i], W[i]}); g[V[i]].push_back({U[i], W[i]}); } function<void(int, int, vector<ll>&)> dfs = [&](int u, int p, vector<ll> &c){ par[u] = p; for(auto [v, cost]:g[u]){ if(v==p){ continue; } c[v]+=c[u] + cost; dfs(v, u, c); } }; dfs(X, -1, c[0]); dfs(Y, -1, c[1]); auto get = [&](ll K){ int ans = 0; vector vis(2, vector<int>(N)); priority_queue<array<ll, 3>, vector<array<ll, 3>>, greater<array<ll, 3>>> pq; // (cost, node, start x or y) pq.push({0, X, 0}); pq.push({0, Y, 1}); while(pq.size()){ auto [cost, u, start] = pq.top(); pq.pop(); if(vis[start][u]){ continue; } vis[start][u]=1; if(K<cost){ break; } //cerr << u << " " << cost << " " << start << endl; ans++; K-=cost; for(auto [v, _]:g[u]){ pq.push({c[start][v], v, start}); } } return ans; }; auto get2 = [&](ll K){ int ans = 0; vector vis(2, vector<int>(N)); priority_queue<array<ll, 3>, vector<array<ll, 3>>, greater<array<ll, 3>>> pq; for(int u=X; ; u=par[u]){ if(min(c[0][u], c[1][u])>K){ return ans; } ans++; if(c[0][u]<c[1][u]){ K-=c[0][u]; vis[0][u]=1; }else{ K-=c[1][u]; vis[1][u]=1; } if(u==Y) break; } for(int u=X; u!=Y; u=par[u]){ for(int start=0; start<2; start++){ for(auto [v, _]:g[u]){ if(vis[start^1][v] and c[start^1][v] <= c[start][v]){ pq.push({c[start][v] - c[start^1][v], v, start}); }else{ pq.push({c[start][v], v, start}); } if(vis[start^1][v] and c[start^1][u] >= c[start][u]){ pq.push({c[start^1][u] - c[start][u], u, start^1}); } } } } while(pq.size()){ auto [cost, u, start] = pq.top(); pq.pop(); if(vis[start][u]){ continue; } vis[start][u]=1; if(K<cost){ break; } ans++; K-=cost; for(auto [v, _]:g[u]){ if(vis[start^1][v] and c[start^1][v] <= c[start][v]){ pq.push({c[start][v] - c[start^1][v], v, start}); }else{ pq.push({c[start][v], v, start}); } if(vis[start^1][v] and c[start^1][u] >= c[start][u]){ pq.push({c[start^1][u] - c[start][u], u, start^1}); } } } return ans; }; return max(get(K), get2(K)); }
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