제출 #105945

#제출 시각아이디문제언어결과실행 시간메모리
105945KastandaBoat (APIO16_boat)C++11
100 / 100
373 ms6648 KiB
#include<bits/stdc++.h> #define pb push_back using namespace std; const int N = 515, Mod = 1e9 + 7; int n, m, A[N], B[N], dp[N + N][N]; long long F[N + N][N]; pair < int , int > P[N + N]; vector < int > U; inline void Add(int &a, int b) { a += b; if (a >= Mod) a -= Mod; if (a < 0) a += Mod; } inline int Power(int a, int b) { int ret = 1; for (; b; b >>= 1, a = 1LL * a * a % Mod) if (b & 1) ret = 1LL * ret * a % Mod; return (ret); } int main() { scanf("%d", &n); for (int i = 1; i <= n; i++) { scanf("%d%d", &A[i], &B[i]); U.pb(A[i]); U.pb(B[i] + 1); } U.pb(0); U.pb(1); sort(U.begin(), U.end()); U.resize(unique(U.begin(), U.end()) - U.begin()); for (int i = 0; i < (int)U.size() - 1; i++) P[m ++] = {U[i], U[i + 1] - 1}; reverse(P, P + m); for (int i = 0; i < m; i++) { int len = P[i].second - P[i].first + 1; F[i][0] = len; for (int lev = 1; lev <= n; lev ++) F[i][lev] = 1LL * F[i][lev - 1] * (len + lev) % Mod * Power(lev + 1, Mod - 2) % Mod; } for (int i = 0; i <= n; i++) dp[m - 1][i] = 1; for (int k = 1; k <= n; k ++) { int sum = 0; for (int i = 1; i < m; i ++) Add(sum, dp[i][0]); for (int i = 0; i < m; i ++, Add(sum, - dp[i][0])) if (A[k] <= P[i].first && P[i].second <= B[k]) for (int j = 0; j <= n; j ++) dp[i][j] = (dp[i][j + 1] + F[i][j] * sum) % Mod; } int tot = 0; for (int i = 0; i < m - 1; i++) Add(tot, dp[i][0]); return !printf("%d\n", tot); }

컴파일 시 표준 에러 (stderr) 메시지

boat.cpp: In function 'int main()':
boat.cpp:26:10: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
     scanf("%d", &n);
     ~~~~~^~~~~~~~~~
boat.cpp:29:14: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
         scanf("%d%d", &A[i], &B[i]);
         ~~~~~^~~~~~~~~~~~~~~~~~~~~~
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