Submission #1057582

#	Time	Username	Problem	Language	Result	Execution time	Memory
1057582		Trent	Dungeons Game (IOI21_dungeons)	C++17	100 / 100	4820 ms	2027380 KiB

dungeons

#include "dungeons.h"
#include "bits/stdc++.h"
using namespace std;
#define forR(i, x) for(int i = 0; i < (x); ++i)
#define REP(i, a, b) for(int i = (a); i < (b); ++i)
typedef long long ll;
typedef vector<int> vi;
int n;
vi s, p, w, l;

const int VLS = 25, ME = 17, MN = 4e5 + 10;
vi skp;
// thl becomes int
struct ch{int t; int by; int thl;};
ch bjp[VLS][MN][ME];
const int INF = 1e8;
ll MXVAL = 1e7;
ll awin[MN];

int trunc(ll val, int lo, int hi) {
    return (int) max((ll) lo, min((ll) hi, val));
}
void init(int n, std::vector<int> s, std::vector<int> p, std::vector<int> w, std::vector<int> l) {
    ::n=n;
    ::s=s, ::p=p, ::w=w, ::l=l;
    skp.push_back(0);
    REP(i, 1, VLS) skp.push_back(1 << (i-1));
    forR(si, VLS) {
    	int val = skp[si];
    	forR(i, n) {
    		if(s[i] <= val) bjp[si][i][0] = {w[i], s[i], INF};
    		else bjp[si][i][0] = {l[i], p[i], s[i]};
    	}
    	REP(e, 1, ME) {
    		forR(i, n) {
    			bjp[si][i][e] = bjp[si][i][e-1];
    			forR(j, 1) {
    				ch nex = bjp[si][i][e];
    				if(nex.t == n) bjp[si][i][e] = nex;
    				else {
    					int nth = bjp[si][nex.t][e-1].thl == INF ? INF : trunc(bjp[si][nex.t][e-1].thl - nex.by, -1, INF);
    					int nby = trunc(bjp[si][nex.t][e-1].by + nex.by, 0, INF);
    					bjp[si][i][e] = {bjp[si][nex.t][e-1].t, nby, min(nex.thl, nth)};
    				}
    			}
    		}
    	}
    }
	awin[n] = 0;
	for(int i = n-1; i >= 0; --i) awin[i] = awin[w[i]] + s[i];
}

struct pii{int a; ll b;};
pii tWin(int x, ll z, int igi) {
    assert(z >= skp[igi]);
    int ci=x; ll cv = z;
    for(int e = ME - 1; e >= 0; --e) {
    	if(ci == n || cv >= MXVAL) return {ci, cv};
    	while(bjp[igi][ci][e].by < INF && (bjp[igi][ci][e].thl == INF || cv < bjp[igi][ci][e].thl)) {
    		cv += bjp[igi][ci][e].by;
    		ci = bjp[igi][ci][e].t;
    		if(ci == n || cv >= MXVAL) return {ci, cv};
    	}
    }
    return {ci, cv};
}
long long simulate(int x, int z) {
    int ci = x;
    ll cv = z;
    forR(ind, VLS) {
    	pii nex = tWin(ci, cv, ind);
    	if(nex.a == n) {
    		return nex.b;
    	}
    	ci=nex.a;
    	cv=nex.b;
    	assert(cv >= s[ci]);
    	cv += s[ci];
    	ci = w[ci];
    	if(cv >= MXVAL) break;
    }
    return cv + awin[ci];
}

• Subtask 1: 11 / 11
• Subtask 2: 26 / 26
• Subtask 3: 13 / 13
• Subtask 4: 12 / 12
• Subtask 5: 27 / 27
• Subtask 6: 11 / 11