제출 #1057433

#제출 시각아이디문제언어결과실행 시간메모리
1057433beaconmcMarathon Race 2 (JOI24_ho_t3)C++14
81 / 100
772 ms252004 KiB
#include <bits/stdc++.h> typedef long long ll; #define FOR(i,x,y) for(ll i=x; i<y; i++) #define FORNEG(i,x,y) for(ll i=x; i>y; i--) using namespace std; const ll maxn = 500005; const ll INF = 100000000000000000; ll tree[maxn*4], tree2[maxn*4]; ll lazy[maxn*4], lazy2[maxn*4]; ll calc(ll k){ return tree[k] + lazy[k]; } void push(ll k){ lazy[k*2] += lazy[k]; lazy[k*2+1] += lazy[k]; tree[k] += lazy[k]; lazy[k] = 0; } void update(ll a, ll b, ll val, ll k=1, ll x=0, ll y=maxn-1){ if (b<x || a>y) return; if (a<=x && y<=b){ lazy[k] += val; return; } ll mid = (x+y)/2; push(k); update(a,b,val,k*2,x,mid); update(a,b,val,k*2+1,mid+1,y); tree[k] = min(calc(k*2), calc(k*2+1)); } ll query(ll a, ll b, ll k=1, ll x = 0, ll y =maxn-1){ if (b<x || a>y) return INF; if (a<=x && y<=b){ return calc(k); } ll mid = (x+y)/2; push(k); return min(query(a, b, k*2, x, mid), query(a,b,k*2+1, mid+1, y)); } ll calc2(ll k){ return tree2[k] + lazy2[k]; } void push2(ll k){ lazy2[k*2] += lazy2[k]; lazy2[k*2+1] += lazy2[k]; tree2[k] += lazy2[k]; lazy2[k] = 0; } void update2(ll a, ll b, ll val, ll k=1, ll x=0, ll y=maxn-1){ if (b<x || a>y) return; if (a<=x && y<=b){ lazy2[k] += val; return; } ll mid = (x+y)/2; push2(k); update2(a,b,val,k*2,x,mid); update2(a,b,val,k*2+1,mid+1,y); tree2[k] = min(calc2(k*2), calc2(k*2+1)); } ll query2(ll a, ll b, ll k=1, ll x = 0, ll y =maxn-1){ if (b<x || a>y) return INF; if (a<=x && y<=b){ return calc2(k); } push2(k); ll mid = (x+y)/2; return min(query2(a, b, k*2, x, mid), query2(a,b,k*2+1, mid+1, y)); } ll a,b,t, n, l; ll arr[2005]; ll cache[2005][2005][2][2]; ll dp(ll x, ll y, ll pos, ll req){ if (cache[x][y][pos][req] != -1) return cache[x][y][pos][req]; if (x==0 && y==n-1){ if (pos==req) return 0; else return 100000000000000000; } if (pos == 0){ ll idk=INF, idk2 = INF; if (y<(n-1))idk = dp(x,y+1,1,req) + abs(arr[x]-arr[y+1])*(n-(y-x)); if (x>0) idk2 = dp(x-1,y,0,req) + abs(arr[x]-arr[x-1])*(n-(y-x)); return cache[x][y][pos][req]=min(idk, idk2); } else if (pos == 1){ ll idk=INF, idk2 = INF; if(x>0) idk = dp(x-1,y,0,req) + abs(arr[y]-arr[x-1])*(n-(y-x)); if (y<(n-1)) idk2 = dp(x, y+1, 1,req) + abs(arr[y]-arr[y+1]) * (n-(y-x)); return cache[x][y][pos][req]=min(idk, idk2); } } int main(){ ios_base::sync_with_stdio(false); cin.tie(NULL); FOR(i,0,maxn*4) tree[i] = 0, lazy[i] = 0, tree2[i] = 0, lazy2[i] = 0; FOR(i,0,2005) FOR(j,0,2005) FOR(k,0,2)FOR(l,0,2) cache[i][j][k][l]=-1; cin >> n >> l; FOR(i,0,n) cin >> arr[i]; sort(arr, arr+n); FOR(i,0,n){ update(i, i, dp(i,i,0,0) + arr[i]*(n+1)); update2(i, i, dp(i,i,0,1) + arr[i]*(n+1)); } ll q; cin >> q; vector<vector<ll>> queries; FOR(i,0,q){ cin >> a >> b >> t; queries.push_back({b, a, t, i}); } sort(queries.begin(), queries.end()); ll prev = 0; ll pos = 0; vector<string> ans(q); for (auto&i : queries){ while (pos < n && arr[pos] <= i[0]){ ll diff = abs(prev-arr[pos]); update(pos, n-1, -diff*(n+1)); update2(pos, n-1, -diff*(n+1)); if (pos != 0) update(0, pos-1, diff*(n+1)); if (pos != 0) update2(0, pos-1, diff*(n+1)); prev = arr[pos]; pos++; } ll diff = abs(prev - i[0]); prev = i[0]; update(pos, n-1, -diff*(n+1)); update2(pos, n-1, -diff*(n+1)); if (pos != 0) update(0, pos-1, diff*(n+1)); if (pos != 0) update2(0, pos-1, diff*(n+1)); ll temp = INF; temp = min(temp, query(0, n-1) + abs(i[1]-arr[0])); temp = min(temp, query2(0, n-1) + abs(i[1]-arr[n-1])); if (temp+n <= i[2]) ans[i[3]] = "Yes"; else ans[i[3]] = "No"; } for (auto&i : ans) cout << i << "\n"; }

컴파일 시 표준 에러 (stderr) 메시지

Main.cpp: In function 'll dp(ll, ll, ll, ll)':
Main.cpp:119:1: warning: control reaches end of non-void function [-Wreturn-type]
  119 | }
      | ^
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