Submission #1057403

#	Time	Username	Problem	Language	Result	Execution time	Memory
1057403		sofijavelkovska	Digital Circuit (IOI22_circuit)	C++17	50 / 100	3084 ms	52664 KiB

circuit

#include "circuit.h"
//#include "stub.cpp"

#include <bits/stdc++.h>
using namespace std;

const long long MOD=1000002022, MAXN=(1<<19);

long long n, m;
vector<int> parent, a;
vector<long long> adj[MAXN];
long long subtree[2*MAXN];
long long factor[2*MAXN];
long long ones[2*MAXN-1], zeros[2*MAXN-1];
long long lazy[2*MAXN-1]={0};

long long power(long long n, long long k)
{
    long long result=1, mul=n;
    for (long long i=0; i<32; i++)
    {
        if (k&(1<<i))
            result=result*mul%MOD;
        mul=mul*mul%MOD;
    }

    return result;
}

void calcsize(long long x)
{
    if (x>=n)
        subtree[x]=0;
    else
        subtree[x]=1;
    for (auto y : adj[x])
    {
        calcsize(y);
        subtree[x]=subtree[x]+subtree[y];
    }

    return;
}

void calcfactor(long long x, long long current)
{
    if (x>=n)
        return;
    long long l=adj[x][0];
    long long r=adj[x][1];
    factor[l]=current*power(2, subtree[r])%MOD;
    factor[r]=current*power(2, subtree[l])%MOD;
    calcfactor(l, factor[l]);
    calcfactor(r, factor[r]);

    return;
}

void propagate(long long x, long long l, long long r)
{
    if (r-l==1)
    {
        lazy[x]=0;
        return;
    }
    if (lazy[x]==0)
        return;
    swap(ones[2*x+1], zeros[2*x+1]);
    swap(ones[2*x+2], zeros[2*x+2]);
    lazy[2*x+1]=(lazy[2*x+1]+1)%2;
    lazy[2*x+2]=(lazy[2*x+2]+1)%2;
    lazy[x]=0;

    return;
}

void update(long long x, long long l, long long r, long long lt, long long rt)
{
    if (l>=rt || r<=lt)
        return;
    if (l>=lt && r<=rt)
    {
        swap(ones[x], zeros[x]);
        lazy[x]=(lazy[x]+1)%2;
        return;
    }
    propagate(x, l, r);
    update(2*x+1, l, (l+r)/2, lt, rt);
    update(2*x+2, (l+r)/2, r, lt, rt);
    ones[x]=(ones[2*x+1]+ones[2*x+2])%MOD;
    zeros[x]=(zeros[2*x+1]+zeros[2*x+2])%MOD;

    return;
}

void buildtree(long long x, long long l, long long r)
{
    if (r-l==1)
    {
        if (l>=m)
        {
            ones[x]=0;
            zeros[x]=0;
            return;
        }
        if (a[l]==1)
        {
            ones[x]=factor[l+n];
            zeros[x]=0;
        }
        else
        {
            ones[x]=0;
            zeros[x]=factor[l+n];
        }
        return;
    }
    buildtree(2*x+1, l, (l+r)/2);
    buildtree(2*x+2, (l+r)/2, r);
    ones[x]=(ones[2*x+1]+ones[2*x+2])%MOD;
    zeros[x]=(zeros[2*x+1]+zeros[2*x+2])%MOD;

    return;
}

void init(int N, int M, vector<int> P, vector<int> A)
{
    n=N;
    m=M;
    parent=P;
    a=A;
    for (int i=1; i<n+m; i++)
        adj[parent[i]].push_back(i);
    calcsize(0);
    calcfactor(0, 1);
    buildtree(0, 0, MAXN);

    return;
}

int count_ways(int l, int r)
{
    l=l-n;
    r=r-n;
    update(0, 0, MAXN, l, r+1);

    return ones[0];
}

• Subtask 1: 0 / 2
• Subtask 2: 7 / 7
• Subtask 3: 0 / 9
• Subtask 4: 4 / 4
• Subtask 5: 12 / 12
• Subtask 6: 27 / 27
• Subtask 7: 0 / 28
• Subtask 8: 0 / 11