이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include<bits/stdc++.h>
#define int long long
#define pb push_back
#define double long double
using namespace std;
const int mod = 1e9 + 7;
const int N = 2e5 + 5;
const int inf = 1e17;
int32_t main(){
ios_base::sync_with_stdio(false), cin.tie(0), cout.tie(0);
int n, m;
cin>>n>>m;
vector<array<int, 3> > adj[N];
vector<int> price[N];
for(int i = 0; i < m; i++){
int u, v, c, p;
cin>>u>>v>>c>>p;
array<int, 3> a1 = {v, c, p};
array<int, 3> a2 = {u, c, p};
adj[u].pb(a1);
adj[v].pb(a2);
}
vector<int> sum(N), cnt(N);
vector<int> seen;
for(int i = 1; i <= n; i++){
price[i].resize(adj[i].size());
for(auto itr: adj[i]){
seen.pb(itr[1]);
sum[itr[1]] += itr[2];
cnt[itr[1]]++;
}
int ind = 0;
for(auto itr: adj[i]){
if(cnt[itr[1]] == 1) price[i][ind] = 0;
else price[i][ind] = sum[itr[1]] - itr[2];
ind++;
}
for(auto itr: seen){
sum[itr] = 0;
cnt[itr] = 0;
}
seen.clear();
}
map<int, int> vis[N];
priority_queue<array<int, 5> > pq;
pq.push({0, 1, 0, 0, 0});
int ans = inf;
while(!pq.empty()){
int cost = -pq.top()[0];
int node = pq.top()[1];
int pre = pq.top()[2];
int prec = pq.top()[3];
int prep = pq.top()[4];
pq.pop();
if(vis[node][pre]) continue;
vis[node][pre] = 1;
if(node == n){
ans = cost;
break;
}
if(pre == 0){ // nothing changed
int ind = 0;
for(auto itr: adj[node]){
if(price[node][ind] > 0) pq.push({-(cost + itr[2]), itr[0], node, itr[1], itr[2]});
if(itr[2] > price[node][ind]) pq.push({-(cost + price[node][ind]), itr[0], 0, 0, 0});
ind++;
}
}
else{ // pre node changed, (- p[pre] in the case you dont change edge[node][nxt])
int ind = 0;
for(auto itr: adj[node]){
if(price[node][ind] > 0) pq.push({-(cost + itr[2]), itr[0], node, itr[1], itr[2]});
if(itr[2] > price[node][ind] - (itr[1] == prec ? prep : 0) ) pq.push({-(cost + price[node][ind] - (itr[1] == prec ? prep : 0)), itr[0], 0, 0, 0});
ind++;
}
}
}
if(ans == inf) cout<<-1<<endl;
else cout<<ans<<endl;
return 0;
}
/*
4 6
1 4 4 4
3 4 1 3
1 3 4 4
2 4 3 1
2 3 3 2
1 2 4 2
5 7
2 3 7 1
1 4 5 1
4 5 3 1
3 4 7 1
2 4 3 1
3 5 6 1
1 2 5 1
*/
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