이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include "aliens.h"
#include <bits/stdc++.h>
#define ll long long
#define sz size()
#define all(x) x.begin(),x.end()
#define vll vector<ll>
#define str string
#define pb push_back
#define pof pop_front()
#define pf push_front
#define pob pop_back()
#define bc back()
using namespace std;
const ll N=1e5+5;
const ll inf = 1e18;
struct Line{
ll m, b, c;
Line(ll m = 0, ll b = 0, ll c = 0) : m(m), b(b), c(c) {}
ll operator () (ll x){return m * x + b;}
bool ok(Line x, Line y){
ll t1 = (x.b - b);
ll b1 = (m - x.m);
ll t2 = (y.b - b);
ll b2 = (m - y.m);
return t1 * b2 >= t2 * b1;
}
};
ll sq(ll x){
return x*x;
}
long long take_photos(int N, int M, int K, vector<int> R, vector<int> C) {
ll i;
ll n=N,m=M,k=K;
vll len, nxt;
vll c, r;
for(auto i : C)c.pb(i);
for(auto i : R)r.pb(i);
{//deleting unnecessary ones
vll mx(m, m), nr;
for(i=0;i<n;i++){
if(r[i] < c[i]) swap(r[i], c[i]);
mx[r[i]] = min(mx[r[i]], c[i]);
}
for(i=m-1;i>=0;i--){
if(mx[i] > i)continue;
if(nr.empty() || mx[nr.bc] > mx[i]){
nr.pb(i);
len.pb(i-mx[i]+1);
}
}
nr.pb(-1), len.pb(-1);//changing indexation
reverse(all(nr));
reverse(all(len));
r=nr;
n=r.size()-1;
k = min(k, n);
}
{//redeclaring and recalculating stuff
c.clear();
c.pb(0);
for(i=1;i<=n;i++){
nxt.pb(r[i] - len[i]);
c.pb(nxt.bc + 1);
len[i - 1] = r[i - 1] - nxt[i - 1] ;
len[i - 1] = max(len[i - 1], 0ll);
}
len[0]=0;
nxt.pb(r[n]);
}
ll ans;
auto calc = [&](ll lm){
vll dp(n + 1, inf);
dp[0]=0;
deque<Line> dq;
vll c(n + 1, 0);
for(i=1;i<=n;i++){
ll x = r[i];
while((ll)dq.sz > 1 && (dq[0](x) > dq[1](x) || (dq[0](x) > dq[1](x) && dq[0].c >= dq[1].c)) ){
dq.pof;
}
if(dq.sz){
dp[i] = sq(r[i]) + dq[0](x) + lm;
c[i] = dq[0].c + 1;
//~ if(lm == 4){
//~ cout<<dp[i]<<endl;
//~ cout<<dq[0].m<<' '<<dq[0].b<<endl;
//~ }
}
if(dp[i] >= sq(r[i] - nxt[0]) + lm){
dp[i] = sq(r[i] - nxt[0]) + lm;
c[i] = 1;
}
ll m = (-2) * nxt[i];
ll b = nxt[i] * nxt[i] - len[i] * len[i] + dp[i];
Line cur = {m, b, c[i]};
while((ll) dq.sz > 1 && dq[dq.sz - 2].ok(dq.bc, cur)) dq.pob;
dq.pb(cur);
}
//~ if(lm == 4){
//~ for(i=1;i<=n;i++){
//~ cout<<dp[i]<<' '<<c[i]<<endl;
//~ }
//~ }
ans = dp[n];
return c[n];
};
{
ll l = 0;
ll r = inf;
while(l + 1 < r){
ll m = (l + r) / 2;
if(calc(m) <= k) r = m;
else l = m;
}
calc(r);
//~ cout<<calc(r)<<' '<<r<<' '<<ans<<endl;
return ans - k * r;
}
}
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