Submission #1056271

#	Time	Username	Problem	Language	Result	Execution time	Memory
1056271		TheQuantiX	Soccer Stadium (IOI23_soccer)	C++17	6 / 100	182 ms	47396 KiB

soccer

#include "soccer.h"
#include <bits/stdc++.h>

using namespace std;
using ll = long long;

constexpr ll INF = 1000000000;

ll n, m, q, k, x, y, a, b, c, d;
vector< vector<int> > v;

bool check(ll x, ll y) {
    if (x < 0 || x >= n) {
        return 0;
    }
    if (y < 0 || y >= n) {
        return 0;
    }
    if (v[x][y]) {
        return 0;
    }
    return 1;
}

int biggest_stadium(int N, std::vector<std::vector<int>> F) {
    n = N;
    v = F;
    ll trees = 0;
    ll mx = n * n;
    for (int i = 0; i < n; i++) {
        for (int j = 0; j < n; j++) {
            if (v[i][j]) {
                trees++;
                mx = min({mx, max({n * n - (i + 1) * (j + 1), n * n - (i + 1) * (n - j), n * n - (n - i) * (j + 1), n * n - (n - i) * (n - j)})});
            }
        }
    }
    return mx;
    int mnx = INF, mny = INF, mxx = -INF, mxy = -INF;
    for (int i = 0; i < n; i++) {
        for (int j = 0; j < n; j++) {
            if (v[i][j] && ((check(i, j + 1) && check(i, j - 1)) || (check(i + 1, j) && check(i - 1, j)))) {
                return 0;
            }
            if (!v[i][j]) {
                mnx = min(mnx, i);
                mxx = max(mxx, i);
                mny = min(mny, j);
                mxy = max(mxy, j);
            }
        }
    }
    pair<int, int> mnxr = {INF, -INF};
    pair<int, int> mnyr = {INF, -INF};
    pair<int, int> mxxr = {INF, -INF};
    pair<int, int> mxyr = {INF, -INF};
    for (int i = 0; i < n; i++) {
        for (int j = 0; j < n; j++) {
            if (i == mnx) {
                mnxr = {min(mnxr.first, j), max(mnxr.second, j)};
            }
            if (j == mny) {
                mnyr = {min(mnyr.first, i), max(mnyr.second, i)};
            }
            if (i == mxx) {
                mxxr = {min(mxxr.first, j), max(mxxr.second, j)};
            }
            if (j == mxy) {
                mxyr = {min(mxyr.first, i), max(mxyr.second, i)};
            }
        }
    }
    if (max(mnxr.second, mxxr.second) - min(mnxr.first, mxxr.first) > max(mnxr.second - mnxr.first, mxxr.second - mxxr.first)) {
        return 0;
    }
    if (max(mnyr.second, mxyr.second) - min(mnyr.first, mxyr.first) > max(mnyr.second - mnyr.first, mxyr.second - mxyr.first)) {
        return 0;
    }
    return n * n - trees;
}

• Subtask 0: 0 / 0
• Subtask 1: 6 / 6
• Subtask 2: 0 / 8
• Subtask 3: 0 / 22
• Subtask 4: 0 / 18
• Subtask 5: 0 / 16
• Subtask 6: 0 / 30