제출 #1056262

#제출 시각아이디문제언어결과실행 시간메모리
1056262Muhammet도로 폐쇄 (APIO21_roads)C++17
5 / 100
35 ms7936 KiB
#include <bits/stdc++.h> #include "roads.h" using namespace std; #define ll long long #define ff first #define ss second vector<ll> minimum_closure_costs(int n, vector<int> u, vector<int> u1, vector<int> w) { vector <pair<ll,pair<ll,ll>>> v; ll s = 0; bool tr = 0; for(int i = 0; i < n-1; i++){ v.push_back({w[i],{u[i],u1[i]}}); if(u1[i] != u[i]+1) tr = 1; s += w[i]; } vector <ll> v1; sort(v.rbegin(), v.rend()); if(*max_element(u.begin(), u.end()) == 0){ ll s2 = s; v1.push_back(s); for(int i = 0; i < n-1; i++){ s2 -= (v[i].ff); v1.push_back(s2); } return v1; } if(tr == 0){ v1.push_back(s); vector <pair<int,int>> v2; for(int i = 0; i < n-1; i++){ v2.push_back({u[i],w[i]}); } sort(v2.begin(), v2.end()); vector <ll> p1(n+1,0), p2(n+1,0); for(int i = 0; i < n-1; i++){ if(i > 0) p1[i] = p1[i-1], p2[i] = p2[i-1]; if(i % 2 == 0) p2[i] += v2[i].ss; else p1[i] += v2[i].ss; } ll mx = max(p1[n-2],p2[n-2]); for(int i = 0; i < n-2; i++){ mx = max(mx,p1[i]+p2[n-2]-p2[i+1]); mx = max(mx,p2[i]+p1[n-2]-p1[i+1]); } v1.push_back(s-mx); for(int i = 2; i < n; i++) v1.push_back(0); return v1; } return vector<ll>(n-1,0); }
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