제출 #1055763

#제출 시각아이디문제언어결과실행 시간메모리
1055763Forested죄수들의 도전 (IOI22_prison)C++17
44 / 100
9 ms1628 KiB
#include <bits/stdc++.h>
using namespace std;

using i32 = int;
using i64 = long long;
template <typename T>
using V = vector<T>;
template <typename T>
using VV = V<V<T>>;
template <typename T>
using VVV = V<V<V<T>>>;

template <typename T>
bool chmin(T &x, const T &y) {
    if (x > y) {
        x = y;
        return true;
    }
    return false;
}
template <typename T>
bool chmax(T &x, const T &y) {
    if (x < y) {
        x = y;
        return true;
    }
    return false;
}

#define OVERRIDE4(a, b, c, d, ...) d
#define REP2(i, n) for (i32 i = 0; i < (i32)(n); ++i)
#define REP3(i, l, r) for (i32 i = (i32)(l); i < (i32)(r); ++i)
#define REP(...) OVERRIDE4(__VA_ARGS__, REP3, REP2)(__VA_ARGS__)
#define PER2(i, n) for (i32 i = (i32)(n)-1; i >= 0; --i)
#define PER3(i, l, r) for (i32 i = (i32)(r)-1; i >= (i32)(l); --i)
#define PER(...) OVERRIDE4(__VA_ARGS__, PER3, PER2)(__VA_ARGS__)
#define ALL(x) begin(x), end(x)
#define LEN(x) (i32) size(x)

void dbg(i32 x) { cerr << x; }
void dbg(i64 x) { cerr << x; }
template <typename T, typename U>
void dbg(pair<T, U> p) {
    cerr << '(' << p.first << ", " << p.second << ')';
}
template <typename T>
void dbg(V<T> arr) {
    cerr << '[';
    REP(i, LEN(arr)) {
        if (i) {
            cerr << ", ";
        }
        dbg(arr[i]);
    }
    cerr << ']';
}
void debug() { cerr << '\n'; }
template <typename Head, typename... Tail>
void debug(Head head, Tail... tail) {
    dbg(head);
    cerr << ", ";
    debug(tail...);
}
#ifdef DEBUGF
#define DBG(...)                       \
    do {                               \
        cerr << #__VA_ARGS__ << " : "; \
        debug(__VA_ARGS__);            \
    } while (false)
#else
#define DBG(...) (void)0
#endif

#include "prison.h"

VV<i32> devise_strategy(i32 n) {
    i32 k = 0;
    while (n >= (1 << (2 * k))) {
        ++k;
    }
    i32 h = 5 * k;
    VV<i32> s(h, V<i32>(n + 1));
    REP(i, h) {
        i32 d = i / 5;
        i32 e = i % 5;
        s[i][0] = !!e;
        REP(j, 1, n + 1) {
            i32 rd = (j >> (2 * (k - 1 - d))) & 3;
            if (e == 0) {
                s[i][j] = d * 5 + rd + 1;
            } else if (rd > e - 1) {
                s[i][j] = -1;
            } else if (rd < e - 1) {
                s[i][j] = -2;
            } else if (d == k - 1) {
                s[i][j] = 0;
            } else {
                s[i][j] = 5 * (d + 1);
            }
        }
    }
    return s;
}
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