이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <algorithm>
#include <bitset>
#include <cstdint>
#include <cstring>
#include <iostream>
#include <limits.h>
#include <math.h>
#include <map>
#include <numeric>
#include <queue>
#include <set>
#include <stack>
#include <string>
#include <vector>
#define int long long
#define loop(X, N) for(int X = 0; X < (N); X++)
#define all(V) V.begin(), V.end()
#define rall(V) V.rbegin(), V.rend()
using namespace std;
typedef vector<int> vi;
typedef vector<vi> vvi;
typedef pair<int, int> ii;
typedef vector<ii> vii;
typedef vector<vector<ii>> vvii;
typedef vector<bool> vb;
typedef vector<vector<bool>> vvb;
typedef uint64_t u64;
typedef int64_t i64;
int n;
string s;
int A, B, C;
int maxCost;
// int cost(int a, int b, int c, int d) {
// if (c == d) return (b - a) * A;
// int res;
// if (a > b) res = cost(a, b - 1, c, d) + A;
// else if (a == b) res = cost(a, b, )
// return res;
// }
vector<vector<vvi>> dp;
int& get(int a, int b, int c, int d) {
if (a == b) {
a = 0;
b = 0;
}
if (c == d) {
c = 0;
d = 0;
}
return dp[a][b][c][d];
}
signed main()
{
ios::sync_with_stdio(0);
cin.tie(0);
//dp cost of building S[a, b] with S[c, d] in clipboard
cin >> n;
cin >> s;
cin >> A >> B >> C;
maxCost = max({A, B, C}) * n;
/*
dp[a][b][c][d]
*/
// loop(i, n) {
// dp[i][i][n][n] = A;
// }
// for (int i = 1; i <= 2 * n; i++) {
// }
/*
dp[a][b][c][d]
dp[a][b][c][d] = min(dp[a][b][c][d], dp[a][b - 1][c][d] + A)
dp[0][0][c][d] = min(dp[c][d][a][b] + B)
if (s[b-(d-c), b] == s[c, d]) dp[a][b][c][d] = min(dp[a][b][c][d], dp[a][b-(d-c)][c][d] + C)
*/
dp = vector<vector<vvi>>(n + 1, vector<vvi>(n + 1, vvi(n + 1, vi(n + 1, maxCost))));
dp[0][0][0][0] = 0;
//loop(idx, (n + 1)) {
loop(c, n + 1) {
for (int d = c; d < n + 1; d++) {
loop(a, n + 1) {
for (int b = a; b < n + 1; b++) {
if (b - 1 >= a)
get(a, b, c, d) = min(get(a, b, c, d), get(a, b - 1, c, d) + A);
if (b - (d - c) >= a && d > c && s.substr(b - (d - c), d - c) == s.substr(c, d - c)) {
get(a, b, c, d) = min(get(a, b, c, d), get(a, b - (d - c), c, d) + C);
}
get(0, 0, a, b) = min(get(0, 0, a, b), get(a, b, c, d) + B);
}
}
}
}
//}
int result = maxCost;
loop(c, n + 1) {
loop(d, n + 1) {
result = min(result, dp[0][n][c][d]);
}
}
cout << result << endl;
// map<string, int> clipBoardCost;
// clipBoardCost[""] = 0;
// loop(i, n) {
// clipBoardCost[s.substr(i, 1)] = A + B;
// }
// for (int sz = 2; sz <= n; sz++) {
// loop(i, n) {
// string goal = s.substr(i, sz);
// string prev = goal;
// prev.pop_back();
// clipBoardCost[goal] = min(clipBoardCost[goal], sz * A);
// }
// }
return 0;
// vvi cost(n + 1, vi(n + 1, maxCost));
// cost[0][0] = 0;
// //cost[0][j] = min(cost[j][i] + B)
// //cost[i][j] = min(cost[i - j][j] + C, cost[i - 1][j] + A)
// loop(i, n + 1) {
// loop(j, n + 1) {
// if (i - 1 >= 0) cost[i][j] = min(cost[i][j], cost[i - 1][j] + A);
// if (i - j >= 0) cost[i][j] = min(cost[i][j], cost[i - j][j] + C);
// cost[0][i] = min(cost[0][i], cost[i][j] + B);
// }
// }
// int result = maxCost;
// loop(j, n + 1) {
// result = min(result, cost[n][j]);
// }
// cout << result << endl;
// return 0;
}
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