Submission #1054808

#	Time	Username	Problem	Language	Result	Execution time	Memory
1054808		j_vdd16	Copy and Paste 3 (JOI22_copypaste3)	C++17	15 / 100	921 ms	2097152 KiB

copypaste3

#include <algorithm>
#include <bitset>
#include <cstdint>
#include <cstring>
#include <iostream>
#include <limits.h>
#include <math.h>
#include <map>
#include <numeric>
#include <queue>
#include <set>
#include <stack>
#include <string>
#include <vector>

#define int long long
#define loop(X, N) for(int X = 0; X < (N); X++)
#define all(V) V.begin(), V.end()
#define rall(V) V.rbegin(), V.rend()

using namespace std;

typedef vector<int> vi;
typedef vector<vi> vvi;
typedef pair<int, int> ii;
typedef vector<ii> vii;
typedef vector<vector<ii>> vvii;
typedef vector<bool> vb;
typedef vector<vector<bool>> vvb;

typedef uint64_t u64;
typedef int64_t i64;

int n;
string s;
int A, B, C;
int maxCost;

// int cost(int a, int b, int c, int d) {
//     if (c == d) return (b - a) * A;
    
//     int res;
//     if (a > b) res = cost(a, b - 1, c, d) + A;
//     else if (a == b) res = cost(a, b, )     

//     return res;
// }

vector<vector<vvi>> dp;
int& get(int a, int b, int c, int d) {
    if (a == b) {
        a = 0;
        b = 0;
    }
    if (c == d) {
        c = 0;
        d = 0;
    }

    return dp[a][b][c][d];
}
signed main()
{
	ios::sync_with_stdio(0);
	cin.tie(0);

    //dp cost of building S[a, b] with S[c, d] in clipboard

    cin >> n;

    cin >> s;

    cin >> A >> B >> C;

    maxCost = max({A, B, C}) * n;
    /*
    dp[a][b][c][d]
    */
    // loop(i, n) {
    //     dp[i][i][n][n] = A;
    // }
    // for (int i = 1; i <= 2 * n; i++) {

    // }

    /*
    dp[a][b][c][d]

    dp[a][b][c][d] = min(dp[a][b][c][d], dp[a][b - 1][c][d] + A)
    dp[0][0][c][d] = min(dp[c][d][a][b] + B)

    if (s[b-(d-c), b] == s[c, d]) dp[a][b][c][d] = min(dp[a][b][c][d], dp[a][b-(d-c)][c][d] + C)

    */
    dp = vector<vector<vvi>>(n + 1, vector<vvi>(n + 1, vvi(n + 1, vi(n + 1, maxCost))));

    dp[0][0][0][0] = 0;
    //loop(idx, (n + 1)) {
        loop(c, n + 1) {
            for (int d = c; d < n + 1; d++) {
                loop(a, n + 1) {
                    for (int b = a; b < n + 1; b++) {
                        if (b - 1 >= a)
                            get(a, b, c, d) = min(get(a, b, c, d), get(a, b - 1, c, d) + A);
                        
                        if (b - (d - c) >= a && d > c && s.substr(b - (d - c), d - c) == s.substr(c, d - c)) {
                            get(a, b, c, d) = min(get(a, b, c, d), get(a, b - (d - c), c, d) + C);
                        }

                        get(0, 0, a, b) = min(get(0, 0, a, b), get(a, b, c, d) + B);
                    }
                }
            }
        }
    //}

    int result = maxCost;
    loop(c, n + 1) {
        loop(d, n + 1) {
            result = min(result, dp[0][n][c][d]);
        }
    }

    cout << result << endl;

    // map<string, int> clipBoardCost;
    // clipBoardCost[""] = 0;
    // loop(i, n) {
    //     clipBoardCost[s.substr(i, 1)] = A + B;
    // }
    // for (int sz = 2; sz <= n; sz++) {
    //     loop(i, n) {
    //         string goal = s.substr(i, sz);
    //         string prev = goal;
    //         prev.pop_back();

    //         clipBoardCost[goal] = min(clipBoardCost[goal], sz * A);
            
    //     }
    // }

    return 0;

    // vvi cost(n + 1, vi(n + 1, maxCost));
    // cost[0][0] = 0;
    
    // //cost[0][j] = min(cost[j][i] + B)
    // //cost[i][j] = min(cost[i - j][j] + C, cost[i - 1][j] + A)
    // loop(i, n + 1) {
    //     loop(j, n + 1) {
    //         if (i - 1 >= 0) cost[i][j] = min(cost[i][j], cost[i - 1][j] + A);
    //         if (i - j >= 0) cost[i][j] = min(cost[i][j], cost[i - j][j] + C);

    //         cost[0][i] = min(cost[0][i], cost[i][j] + B);
    //     }
    // }

    // int result = maxCost;
    // loop(j, n + 1) {
    //     result = min(result, cost[n][j]);
    // }

    // cout << result << endl;

	// return 0;
}

• Subtask 1: 1 / 1
• Subtask 2: 0 / 5
• Subtask 3: 14 / 14
• Subtask 4: 0 / 10
• Subtask 5: 0 / 32
• Subtask 6: 0 / 38