제출 #1054527

#제출 시각아이디문제언어결과실행 시간메모리
1054527MinbaevBitaro’s Party (JOI18_bitaro)C++17
7 / 100
1595 ms524288 KiB
#include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #pragma GCC target("avx,avx2,fma") #pragma GCC optimize("Ofast,unroll-loops") using namespace std; using namespace __gnu_pbds; #define pb push_back #define all(x) x.begin(),x.end() #define rall(x) x.rbegin(),x.rend() #define f first #define s second #define int long long #define ll long long #define pii pair<int,int> #define ar array template<class T>bool umax(T &a,T b){if(a<b){a=b;return true;}return false;} template<class T>bool umin(T &a,T b){if(b<a){a=b;return true;}return false;} template<class T> using st = tree<T, null_type, less_equal<T>, rb_tree_tag, tree_order_statistics_node_update>; const int inf = 1e17 + 7; const int mod = 1e9 + 7; const int N = 3e5 + 5; const int md = 998244353; int binpow(int a, int b){ if(b == 0)return 1; if(b % 2 == 0){ int c = binpow(a,b/2); return (c*c)%mod; } return (binpow(a,b-1)*a)%mod; } int divi(int a, int b){ return (a*(binpow(b,mod-2)))%mod; } int n,m,k; int sz = 400; vector<int>g[N], gg[N]; vector<pii>calc[N]; void solve(){ int q; cin >> n >> m >> q; while(m--){ int a,b; cin >> a >> b; //~ g[a].pb(b); g[b].pb(a); gg[a].pb(b); } vector<int>reach, dist(n+1), last(n+1); for(int i = 1;i<=n;i++){ reach.pb(i); for(auto x:g[i]){ for(auto [cost, to] : calc[x]){ if(last[to] == i){ umax(dist[to], cost + 1); } else { dist[to] = cost + 1; last[to] = i; reach.pb(to); } } } sort(all(reach),[&](int a, int b){ return dist[a] > dist[b]; }); for(int j = 0;j<min(sz, (int)reach.size());j++){ calc[i].pb({dist[reach[j]],reach[j]}); } reach.clear(); } int timer = 1; vector<int> del(n+1, 0); while(q--){ int v; cin >> v >> k; for(int i = 0;i < k; i++){ int x; cin >> x; del[x] = timer; } if(k < sz){ int ans = -1; for(auto [d, u] : calc[v]){ if(del[u] != timer){ ans = d; break; } } cout << ans << '\n'; }else{ vector<int> d(n+1, -1); for(int i = 1;i <= n; i++){ if(del[i] != timer){ d[i] = max(d[i], 0ll); } for(int to : gg[i]){ if(d[i] != -1) d[to] = max(d[to], d[i] + 1); } } cout << d[v] << '\n'; } timer++; } } /* 5 6 1 5 3 5 4 3 1 3 2 4 2 2 1 2 1 5 1 2 3 4 4 3 1 2 5 */ signed main() { // freopen("seq.in", "r", stdin); // freopen("seq.out", "w", stdout); ios_base::sync_with_stdio(0);cin.tie(NULL);cout.tie(NULL); int tt=1;//cin>>tt; while(tt--)solve(); }
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