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답안 #1051072

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
1051072 2024-08-09T19:16:31 Z beaconmc Spy 3 (JOI24_spy3) C++17
0 / 100
 1000 ms 10332 KB 
#include "Aoi.h"
#include <bits/stdc++.h>
 
typedef long long ll;
#define FOR(i,x,y) for(ll i=x; i<y; i++)
#define FORNEG(i,x,y) for(ll i=x; i>y; i--)

using namespace std;

namespace {

const ll INF = 10000000000000000;
const ll maxn = 10005;
vector<vector<ll>> edges[maxn];
vector<ll> prevs[maxn];
ll dists[maxn];
bool visited[maxn];


}  // namespace


string aoi(int N, int M, int Q, int K, vector<int> A,vector<int> B, vector<long long> C,
                vector<int> T, vector<int> X) {
    string ans;

    FOR(i,0,M){
        edges[A[i]].push_back({B[i], C[i], i});
        edges[B[i]].push_back({A[i], C[i], i});
    }
    FOR(i,0,Q){
        FOR(k,0,maxn) dists[k] = INF, prevs[k] = {-1, -1}, visited[k] = 0;


        priority_queue<vector<ll>> pq;

        dists[0] = 0;

        pq.push({0, 0});
        while (pq.size()){
            vector<ll> node = pq.top();
 
            if (node[1] == T[i]) break;
            pq.pop();
            node[0] = -node[0];
            for (auto&i : edges[node[1]]){
                if (dists[i[0]] > node[0] + i[1]){
                    prevs[i[0]] = {node[1], i[2]};
                    dists[i[0]] = node[0] + i[1];
                    pq.push({-dists[i[0]], i[0]});
                }
            }
        }
        set<ll> stuff;
        ll cur = T[i];

        
        while (prevs[cur][1] != -1){
            stuff.insert(prevs[cur][1]);
            cur = prevs[cur][0];
        }


        FOR(j,0,K){
            if (stuff.count(X[j])) ans += '1';
            else ans += '0';
        }

    }
    return ans;


}

#include "Bitaro.h"
#include <bits/stdc++.h>
 
typedef long long ll;
#define FOR(i,x,y) for(ll i=x; i<y; i++)
#define FORNEG(i,x,y) for(ll i=x; i>y; i--)

using namespace std;
namespace {
const ll INF = 10000000000000000;
const ll maxn = 10005;
vector<vector<ll>> edges[maxn];
vector<ll> prevs[maxn];
ll dists[maxn];
bool visited[maxn];
}  // namespace




void bitaro(int N, int M, int Q, int K, vector<int> A, vector<int> B,
            vector<long long> C, vector<int> T, vector<int> X,
            string s) {



    FOR(i,0,M){
        edges[A[i]].push_back({B[i], C[i], i});
        edges[B[i]].push_back({A[i], C[i], i});
    }
    FOR(i,0,Q){

        FOR(k,0,maxn) dists[k] = INF, prevs[k] = {-1, -1}, visited[k] = 0;
        unordered_set<ll> idk;
        FOR(j, K*i, K*(i+1)){
            if (s[j] == '1') idk.insert(X[j-K*i]);
        }

        unordered_set<ll> idkman;
        for (auto&i : X) idkman.insert(i);

        FOR(i,0,maxn){
            for (auto&j : edges[i]){
                if (idk.count(j[2])) j[1] = 1;
                else if (idkman.count(j[2])) j[1] = INF;
            }
           

        }


        priority_queue<vector<ll>> pq;

        dists[0] = 0;

        pq.push({0, 0});
        while (pq.size()){
            vector<ll> node = pq.top();
            if (node[1] == T[i]) break;
            pq.pop();
            node[0] = -node[0];
            for (auto&i : edges[node[1]]){
                if (dists[i[0]] > node[0] + i[1]){
                    prevs[i[0]] = {node[1], i[2]};
                    dists[i[0]] = node[0] + i[1];
                    pq.push({-dists[i[0]], i[0]});
                }
            }
        }

        vector<int> stuff;

        ll cur = T[i];
        
        while (prevs[cur][1] != -1){
            stuff.push_back(prevs[cur][1]);
            cur = prevs[cur][0];
        }

        reverse(stuff.begin(), stuff.end());

        answer(stuff);



    }


}

Subtask #1
0.0 / 100.0

# 결과 실행 시간 메모리 Grader output
1 Partially correct 26 ms 9028 KB Partially correct
2 Correct 2 ms 2324 KB Output is correct
3 Partially correct 65 ms 8504 KB Partially correct
4 Partially correct 63 ms 8064 KB Partially correct
5 Partially correct 81 ms 8380 KB Partially correct
6 Partially correct 74 ms 8376 KB Partially correct
7 Partially correct 72 ms 8568 KB Partially correct
8 Partially correct 73 ms 8640 KB Partially correct
9 Partially correct 63 ms 7868 KB Partially correct
10 Correct 24 ms 8052 KB Output is correct
11 Partially correct 68 ms 8592 KB Partially correct
12 Correct 79 ms 8444 KB Output is correct
13 Partially correct 77 ms 8376 KB Partially correct
14 Partially correct 59 ms 8632 KB Partially correct
15 Correct 64 ms 8256 KB Output is correct
16 Correct 16 ms 7956 KB Output is correct
17 Partially correct 90 ms 8464 KB Partially correct
18 Partially correct 101 ms 8516 KB Partially correct
19 Partially correct 141 ms 10280 KB Partially correct
20 Partially correct 93 ms 10228 KB Partially correct
21 Partially correct 144 ms 10332 KB Partially correct
22 Execution timed out 1029 ms 5084 KB Time limit exceeded
23 Halted 0 ms 0 KB -