Submission #1049597

#TimeUsernameProblemLanguageResultExecution timeMemory
1049597GrindMachineSparklers (JOI17_sparklers)C++17
0 / 100
0 ms348 KiB
#include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> using namespace std; using namespace __gnu_pbds; template<typename T> using Tree = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>; typedef long long int ll; typedef long double ld; typedef pair<int,int> pii; typedef pair<ll,ll> pll; #define fastio ios_base::sync_with_stdio(false); cin.tie(NULL) #define pb push_back #define endl '\n' #define sz(a) (int)a.size() #define setbits(x) __builtin_popcountll(x) #define ff first #define ss second #define conts continue #define ceil2(x,y) ((x+y-1)/(y)) #define all(a) a.begin(), a.end() #define rall(a) a.rbegin(), a.rend() #define yes cout << "Yes" << endl #define no cout << "No" << endl #define rep(i,n) for(int i = 0; i < n; ++i) #define rep1(i,n) for(int i = 1; i <= n; ++i) #define rev(i,s,e) for(int i = s; i >= e; --i) #define trav(i,a) for(auto &i : a) template<typename T> void amin(T &a, T b) { a = min(a,b); } template<typename T> void amax(T &a, T b) { a = max(a,b); } #ifdef LOCAL #include "debug.h" #else #define debug(...) 42 #endif /* refs: edi stress tested to figure out the bug (ans = 0 case was bugged) ac code used for stress testing: https://oj.uz/submission/1043916 */ const int MOD = 1e9 + 7; const int N = 1e5 + 5; const int inf1 = int(1e9) + 5; const ll inf2 = ll(1e18) + 5; void solve(int test_case) { ll n,k,t; cin >> n >> k >> t; vector<ll> a(n+5); rep1(i,n) cin >> a[i]; auto ok = [&](ll s){ vector<ll> cnt(n+5); rep1(l,k){ for(int r = k; r <= n; ++r){ if(l == 1 and r == n) conts; ll len = r-l+1; bool ok = false; __int128 lim = (__int128)2*len*t*s; // l --> l-1 if(l-1){ if(a[r]-a[l-1] <= lim){ ok = true; } } // r --> r+1 if(r+1 <= n){ if(a[r+1]-a[l] <= lim){ ok = true; } } if(ok) cnt[len]++; } } rep1(i,n-1){ if(!cnt[i]){ return false; } } return true; bool dp[n+5][n+5]; memset(dp,0,sizeof dp); dp[k][k] = 1; rev(l,n,1){ for(int r = l; r <= n; ++r){ ll len = r-l+1; if(!dp[l][r]) conts; __int128 lim = (__int128)2*len*t*s; // l --> l-1 if(l-1){ if(a[r]-a[l-1] <= lim){ dp[l-1][r] = 1; } } // r --> r+1 if(r+1 <= n){ if(a[r+1]-a[l] <= lim){ dp[l][r+1] = 1; } } } } return dp[1][n]; }; ll lo = 0, hi = inf1; ll ans = -1; while(lo <= hi){ ll mid = (lo+hi) >> 1; if(ok(mid)){ ans = mid; hi = mid-1; } else{ lo = mid+1; } } cout << ans << endl; } int main() { fastio; int t = 1; // cin >> t; rep1(i, t) { solve(i); } return 0; }
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