#pragma GCC optimize("O1,O2,O3,Ofast,unroll-loops")
#include <bits/stdc++.h>
#include <string>
#include <iostream>
#include <cmath>
#include <numeric>
#include "keys.h"
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
typedef long double ld;
typedef pair<int, int> pi;
typedef pair<int, int> pl;
typedef pair<ld, ld> pd;
typedef vector<int> vi;
typedef vector<bool> vb;
typedef vector<vector<int>> vvi;
typedef vector<ld> vd;
typedef vector<ll> vl;
typedef vector<pi> vpi;
typedef vector<pl> vpl;
#define FOR(i, a, b) for (int i = a; i < (b); i++)
#define F0R(i, a) for (int i = 0; i < (a); i++)
#define FORd(i, a, b) for (int i = (b)-1; i >= a; i--)
#define F0Rd(i, a) for (int i = (a)-1; i >= 0; i--)
#define trav(a, x) for (auto &a : x)
#define uid(a, b) uniform_int_distribution<int>(a, b)(rng)
#define len(x) (int)(x).size()
#define mp make_pair
#define pb push_back
#define F first
#define nl endl
#define S second
#define lb lower_bound
#define ub upper_bound
#define aint(x) x.begin(), x.end()
#define raint(x) x.rbegin(), x.rend()
#define ins insert
const int MOD = 1000000007;
vector<vpi> paths(3e5+10,vpi());
int n;
vi visited;
int ans = 1e9;
vi counter;
void bfs(int pos,vi r){
queue<int> nodes;
set<int> keys;
vvi nokeys(3e5+10,vi());
int cnt = 0;
nodes.push(pos);
while(!nodes.empty()){
if(cnt > ans)break;
int node = nodes.front();nodes.pop();
if(visited[node])continue;
cnt++;
keys.insert(r[node]);
visited[node] = 1;
for(int edge:nokeys[r[node]]){
nodes.push(edge);
}
nokeys[r[node]] = vi();
for(pi edge:paths[node]){
if(keys.count(edge.S)){
nodes.push(edge.F);
if(counter[edge.F] > ans){
counter[pos] = counter[edge.F];
return;
}
}else{
nokeys[edge.S].pb(edge.F);
}
}
}
counter[pos] = cnt;
ans = min(ans,cnt);
}
vi find_reachable(vi r, vi u, vi v, vi c) {
FOR(i,0,u.size()){
paths[u[i]].pb({v[i],c[i]});
paths[v[i]].pb({u[i],c[i]});
}
n = r.size();
counter = vi(n,0);
FOR(i,0,n){
visited = vi (n,0);
bfs(i,r);
}
// for(int a:counter)cout << a << " ";
// cout << endl;
FOR(i,0,n){
if(counter[i] == ans)counter[i] = 1;
else counter[i] = 0;
}
return counter;
}
