제출 #1047879

#제출 시각아이디문제언어결과실행 시간메모리
1047879clementineArranging Shoes (IOI19_shoes)C++17
0 / 100
0 ms348 KiB
#include "shoes.h" #include <bits/stdc++.h> using namespace std; typedef long long ll; int st[400000]; void update(int cur, int lo, int hi, int l, int r, int val) { if ((r < lo) || (l > hi)) { return; } if(( lo >= l ) && ( hi <= r)) { st[cur] +=val; return; } int mid = (lo + hi) / 2; update(2 * cur, lo, mid, l , r, val); update(2 * cur + 1, mid + 1, hi, l, r, val); } int query(int cur, int lo, int hi, int idx) { if (lo == hi) { return st[cur]; } int mid = (lo + hi) / 2; if( idx <= mid) { return st[cur] + query( 2 * cur, lo, mid, idx); } else { return st[cur] + query( 2 * cur + 1, mid + 1, hi, idx); } } long long count_swaps(vector<int> s) { int n = s.size(); vector<deque<int>> szidx( 2 * n + 1); vector<bool> there(n + 1, 1); for(int i = 1; i <= n; i ++) { int val = s[i-1]; szidx[val + n].push_back(i); } /* for(auto sz: szidx) { for (auto a : sz) { cout << a << " "; } cout << '\n'; } cout << '\n'; */ ll ans = 0; vector<int> sorted; for(int i = 1; i <=n; i ++) { if(there[i]) { int pair = szidx[(0-s[i-1]) + n].front(); szidx[(0-s[i-1]) + n].pop_front(); szidx[s[i-1] + n].pop_front(); ans += pair + (query(1,1,n,pair)) - (i + query(1,1,n,i)) - 1; cout << i << " " << pair << " : " <<pair + (query(1,1,n,pair)) - (i + query(1,1,n,i)) - 1 << '\n'; there[pair] = false; sorted.push_back(s[i-1]); sorted.push_back(s[pair-1]); update(1,1,n, i, pair, 1 ); } } for(int i = 0; i < n; i +=2) { if(sorted[i] > 0) { ans +=1; } } return 0; }
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