제출 #104760

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
104760		mzhao	Bitaro, who Leaps through Time (JOI19_timeleap)	C++11	4 / 100	3068 ms	8728 KiB

timeleap

#include <bits/stdc++.h>
using namespace std;

#ifdef DEBUG
#define D(x...) printf(x)
#else
#define D(x...)
#endif

#define MN 300009
#define ll long long

int N, Q, L[MN], R[MN];

int main() {
	scanf("%d%d", &N, &Q);
	for (int i = 1; i < N; i++) {
		scanf("%d%d", &L[i], &R[i]);
	}
	for (int _ = 0, T, A, B, C, D; _ < Q; _++) {
		scanf("%d", &T);
		if (T == 1) {
			scanf("%d%d%d", &A, &B, &C);
			L[A] = B; R[A] = C;
		} else {
			scanf("%d%d%d%d", &A, &B, &C, &D);
			ll cur = 0;
			if (A <= C) {
				for (int i = A; i < C; i++) {
					B = max(B, L[i]);
					if (B >= R[i]) {
						cur += B-R[i]+1;
						B = R[i]-1;
					}
					B++;
				}
				if (B > D) cur += B-D;
			} else {
				for (int i = A-1; i >= C; i--) {
					B = max(B, L[i]);
					if (B >= R[i]) {
						cur += B-R[i]+1;
						B = R[i]-1;
					}
					B++;
				}
				if (B > D) cur += B-D;
			}
			printf("%lld\n", cur);
		}
	}
}

컴파일 시 표준 에러 (stderr) 메시지

timeleap.cpp: In function 'int main()':
timeleap.cpp:16:7: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
  scanf("%d%d", &N, &Q);
  ~~~~~^~~~~~~~~~~~~~~~
timeleap.cpp:18:8: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
   scanf("%d%d", &L[i], &R[i]);
   ~~~~~^~~~~~~~~~~~~~~~~~~~~~
timeleap.cpp:21:8: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
   scanf("%d", &T);
   ~~~~~^~~~~~~~~~
timeleap.cpp:23:9: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
    scanf("%d%d%d", &A, &B, &C);
    ~~~~~^~~~~~~~~~~~~~~~~~~~~~
timeleap.cpp:26:9: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
    scanf("%d%d%d%d", &A, &B, &C, &D);
    ~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~

• Subtask 1: 4 / 4
• Subtask 2: 0 / 30
• Subtask 3: 0 / 66